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3 years ago

HELP PLZ DUE IN 30 MIN

Mathematics

1 answer:

MaRussiya [10]3 years ago

7 0

9514 1404 393

Answer:

D. a ║ b

Step-by-step explanation:

If we figure the other angle of each linear pair, we can directly compare angles to see if corresponding angles are the same. Where they are the same, the lines are parallel.

Line a is parallel to line b.

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allsm [11]

Answer:

8:27

Step-by-step explanation:

Let Small cone be A, Large cone be B.

#Compare volumes to find scale factor.

$\ Volume \ scale \ factor= \frac{Vol A}{Vol B}\\=\frac{320}{1080}\\=\frac{8}{27} \ or\ 8:27$

5 0

3 years ago

If the length of the segment AB is 5, and BC is 9, and CD is three, find the difference between the furthest and shortest possib

S_A_V [24]

9514 1404 393

Answer:

E. 16

Step-by-step explanation:

If the order of points on the line is ABCD, the distance between A and D is ...

AB +BC +CD = 5 + 9 + 3 = 17

If the order of points on the line is BADC, the distance between A and D is ...

BC -BA -DC = 9 -5 -3 = 1

Then the difference between the longest and shortest possible distances AD is ...

17 - 1 = 16 . . . . matches choice E

5 0

3 years ago

Someone able to solve this ? Please

alexandr1967 [171]

Type it into Desmos graphing calculator it is so helpful.

Have a merry Christmas!

6 0

3 years ago

Read 2 more answers

Help give me the formula and the answer and plz explain so I also benefit:)

Fudgin [204]

I think 48 cubic cm..... (Tell me if I did it wrong or not)

4 0

3 years ago

Find the area of the entire figure.

MakcuM [25]

Answer:

$\large\boxed{A=171.555\ in^2}$

Step-by-step explanation:

We have the right triangle and the trapezoid.

The formula of an area of a right triangle:

$A_{triangle}=\dfrac{ab}{2}$

a, b - legs

We have the length of the legs 12in and 13.42 in. Substitute:

$A_{triangle}=\dfrac{(12)(13.42)}{2}=80.52\ in^2$

The formula of an area of a trapezoid:

$A_{trapezoid}=\dfrac{(b_1+b_2)h}{2}$

b₁, b₂ - bases

h - height

We have the length of the bases 18in and 11.75in and the length of the height 6.12in. Substitute:

$A_{trapezoid}=\dfrac{(18+11.75)(6.12)}{2}=\dfrac{(29.75)(6.12)}{2}=91.035\ in^2$

The area of the figure:

$A=A_{triangle}+A_{trapezoid}$

Substitute:

$A=80.52+91.035=171.555\ in^2$

5 0

4 years ago