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3 years ago

WRITING TO EXPLAIN, HOW COULD YOU USE 5 X 6 =30 TO FIND THE PRODUCT OF 6 X6 ?

2 answers:

8 0

Using 5*6=30, you can add 6 to the 30, which equals 36.

SO just add 6 to your answer of 5*6, the answer you will get is 36.

sineoko [7]3 years ago

4 0

Yes you can. Just do the equation and compare the sums

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60/1 in a equivalent ratio

Elena-2011 [213]

60 /1 = 120 /2 = 180 /3

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8 0

3 years ago

Read 2 more answers

Suppose it takes 45 hours for robot A to construct a new robot. Working together with robot B, it takes 25 hours for both robots

Len [333]

Answer:

56 hours 25 minutes

Step-by-step explanation:

Given:

Suppose it takes 45 hours for robot A to construct a new robot

It takes 25 hours for both robots to construct a new robot.

Question asked:

How long would it take robot B to construct a new robot, working alone ?

Solution:

Let the time taken by robot B to construct new robot = $x$

By robot A

It takes 45 hours to construct = 1 new robot

It takes 1 hour to construct = $\frac{1}{45} \ new\ robot$

By robot B

It takes $x$ hours to construct = 1 new robot

It takes 1 hour to construct = $\frac{1}{x}$ new robot

By working together

It takes 25 hours to construct = 1 new robot

It takes 1 hour to construct = $\frac{1}{25} \ new\ robot$

$\frac{1}{25}$ new robot is constructed in = 1 hour

New robot is constructed by both working together in 1 hour = New robot is constructed by robot A in 1 hour + New robot is constructed by robot B in 1 hour

$\frac{1}{25} =\frac{1}{45} +\frac{1}{x} \\$

Subtracting both sides by $\frac{1}{45}$

$\frac{1}{25}-\frac{1}{45} =\frac{1}{45} -\frac{1}{45}+\frac{1}{x} \\\\\frac{1}{25}-\frac{1}{45} =\frac{1}{x}\\\\ Taking\ LCM \ of \ 25\ and\ 45,\ we\ got\ 225$

$\frac{9-5}{225} =\frac{1}{x} \\ \\ \frac{4}{225} =\frac{1}{x}\\\\ By\ cross \ multiplication\\4\times x=225\\Dividing\ both\ sides\ by\ 4\\x=56.25\ hours$

Thus, robot B would take 56 hours 25 minutes to construct a new robot, working alone.

4 0

3 years ago

Read 2 more answers

11x + x helppp plzzz

Juliette [100K]

This answers would be 12x

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3 years ago

What is the value of x in the circle below? If necessary round your answer to the nearest tenth. I AM FAILING THIS CLASS I JUST

emmainna [20.7K]

Since we know that the 38 is being bisected (which we can tell by the fact that the line hits it perpendicularly), we know that from the intersection to the edge of the circle is 19. From this we can create a right triangle in which the legs are 10 and 19 and the hypotenuse is a radius of the circle. Since x is also a radius of the circle, all we have to do is use that information to find the hypotenuse using the Pythagorean Theorem and we have x.

Pythagorean Theorem
$a^{2}$ + $b^{2}$ = $c^{2}$
$10^{2}$ + $19^{2}$ = $x^{2}$
100 + 361 = $x^{2}$
461 = $x^{2}$
x = $\sqrt{461}$ or about 21.47

8 0

3 years ago

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Match the following items by evaluating the expression for x = -7. x-2 x-1 x0 x1 x2

frosja888 [35]

Answer:

${x}^{ - 2} = \frac{1}{ {x}^{2} } \: \: –> {7}^{ - 2} = \frac{1}{ {7}^{2} } = \frac{ 1}{49} \\ \\ {x}^{ - 1} = \frac{1}{ {x}^{1} } \: –> {7}^{ - 1} = \frac{1}{ {7}^{1} } = \frac{1}{7} \\ \\ {x}^{0} –> {7}^{0} = 1 \\ \\ {x}^{1} –> {7}^{1} = 7 \\ \\ {x}^{2} –> {7}^{2} = 49$

7 0

2 years ago