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3 years ago

What is 8 1/3 - 2 2/3 =?

Mathematics

1 answer:

Rom4ik [11]3 years ago

5 0

Answer:

17/3

Step-by-step explanation:

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balandron [24]

Answer:

Step-by-step explanation:

hello :

look this solution :

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3 years ago

First Data Corp. records indicate that in 2005, 43% of adult email users received a phishing email. A phishing email replicates

ra1l [238]

Answer:

P(x) = 45/100 = 0.45

Mean sample distribution = probability x number sampled by the survey.

Mean sample distribution = 0.45 x 800 = 360.00 to two decimal places.

Step-by-step explanation:

Convert the percentage to decimal probability.

45%. P(x) = 45/100 = 0.45

If there are ranges of probability values, we construct a probability distribution table. This is not necessary in the case of one probability value(45%)

Multiply the probability by the number adults to be surveyed on whether they have received phishing emails.

0.45 x 800 = 360.

Here, we assume that the 45% recorded by 2005 data, is still valid for the recent trends.

5 0

3 years ago

Read 2 more answers

HELP!

artcher [175]

Answer:

B.Obtuse

as shown in the pictures that you put the angel is obtuse

6 0

3 years ago

What is 21/11 as a mixed fraction

castortr0y [4]

Answer:

the answer is

1 10/11

4 0

3 years ago

Read 2 more answers

Can you please help me out

Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

$\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}$

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

$\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}$ $\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}$

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

$\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}$

Hence, the best option is G.

5 0

1 year ago