An agency is studying the income of store managers in the retail industry. A random sample of 25 managers reveals a sample mean
1 answer:
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Answer:
(-2.2, -1.6), (3, 1)
Step-by-step explanation:
You don't have to go far to find the equations. They are right there in your problem statement. Perhaps you want to find the solutions to the equations.
Use the first equation to write an expression for x, then substitute that into the second equation:
x = 2y +1
y^2 -3(2y+1)(y) +8 = 0
-5y^2 -3y +8 = 0
-(5y +8)(y -1) = 0
y = -8/5 or y = 1
The corresponding values of x are ...
x = 2(-8/5)+1 = -11/5
x = 2(1) +1 = 3
The solutions are (x, y) = (-2.2, -1.6) and (3, 1).
Answer: d) 0.9693
<u>Step-by-step explanation:</u>
refer to the z-table attached.
The table shows the percent from the MEAN. The percent below the mean is 50% so that needs to be added to the value in the table.
Look on the left side for 1.8 and the top for 0.07 (which is 1.87).
The value is 0.4693 --> add 0.5 to that value to get 0.9693.
