Y= -4/5 + 25
.....................
If A(t) is the amount of salt in the tank at time t, then A(0) = 50 g and
A'(t) = (1 g/L)*(3 L/min) - (A(t)/120 g/L)*(3 L/min)

Multiply both sides by
, so that the left side can be condensed as the derivative of a product:


Integrate both sides and solve for A(t).


Given that A(0) = 50 g, we have

so that the amount of salt in the tank at time t is

Answer:
x-30y=100 and 10y=x-20
Step-by-step explanation:
Answer: dilation
Step-by-step explanation: