Sub x = 2-y^2 to Q, we get:
Q = 3(2-y^2)*y^2
let y^2 = k
Q = 3(2-k)k = 3(2k-k^2)
2k-k^2 has a max when k = 1
Then y^2 = 1 -> y = 1 or -1
Answer:
Undefined
Step-by-step explanation:
This is horizontal line, so the slope is undefined.
Answer:
x=1
y=-4
Step-by-step explanation:
Since -x-3=y subsitue that in at the top equation




Plug x=1 back into the equation to solve for y.


Answer:
15
Step-by-step explanation: