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Varvara68 [4.7K]
3 years ago
5

An acute triangle has sides measuring 10 cm and 16 cm. The length of the third side is unknown. Which best describes the range o

f possible values for the third side of the triangle? A x 18.9 B 12.5 26 D 6 < x < 26
Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
3 0

Solution:

12.5 < x < 18.9

Reason:

To solve this problem, we can apply Pythagorean's theorem.

To find the upper bound:

We can set the two given legs as the 2 legs of a right triangle. This allows us to keep the angle under 90 degrees. So if we set the legs to be 10 and 16, then the third side must be:

10^2 + 16^2 = x^2

x^2 = 356

x is roughly equal to 18.9

For the lower bound, this time, we set x as one of the legs, and 10 as the other let. Since we know that the longest side is 16, we can set up an equation again:

x^2 + 10^2 = 16^2

x^2 = 16^2 - 10^2

x^2 = 156

x is roughly equal to 12.5

So we have found the bounds to be 12.5 < x < 18.9

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wel
I think you need to use the SoHCaHToA method here.

S means sin
C means cos
T means tan
O means opposite
H means hypotenuse
A means adjacent

The hypotenuse is the longest side in a right angled triangle.

The adjacent is the side between the angle and the right angle.

The opposite is the side that is left.

If you have the value of the opposite cross all of the o's out. The same with the other sides. If only one type of letter is crossed out, cross out the type of letter that stands for the length you want to find. The part of the word with two crosses tells you what function to use (sin, cos or tan)

In this example, the function used will be sin.

sinx°=o÷h
cosx°=a÷h
tanx°=o÷a

since we are using sin, the formula we will use is :

sinx°=o÷h

Then you plug in what you know.

sin30°=30÷h
h=30÷sin30°
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If there was a case when you needed to work out an angle, inverse sin, or cos, or tan would be used.
7 0
4 years ago
At a school with 100? students, 33 were taking? Arabic, 32 ?Bulgarian, and 40 Chinese. 9 students take only? Arabic, 12 take onl
Stels [109]

Answer: The answer is 4 and 32.

Step-by-step explanation: Let "A", "B" and "C" represents the set of students who were taking Arabic, Bulgarian and Chinese respectively.

The, according to the given information, we have

n(A)=33,~~n(B)=32,~~n(C)=40,~~n(A\cap B)=14.

Let 'p' represents the number of students who take all the three languages, then

n(A\cap B\cap C)=p.

Also,

n(A)-n(A\cap B)-n(A\cap C)+n(A\cap B\cap C)=9\\\\\Rightarrow n(A\cap B)+n(A\cap C)=24+p~~~~~~~~~~~~~~(a),\\\\n(A\cap B)+n(B\cap C)=20+p~~~~~~~~~~~~~~(b),\\\\n(B\cap C)+n(A\cap C)=20+p~~~~~~~~~~~~~~~(c).

From here, we get after subtracting equation(c) from (b) that

n(A\cap B)=n(A\cap C)=14.

Therefore,

p=14+14-24=4, and from equation (a), we find

n(B\cap C)=24-14=10.

Thus,

n(A\cap B\cap C)=4 and

n(A\cup B\cup C)=n(A)+n(B)+n(C)-n(A\cap B)-n(B\cap C)-n(A\cap C)+n(A\cap B\cap C)\\\\\Rightarrow n(A\cap B\cap C)=33+32+40-9-12-20+4\\\\\Rightarrow n(A\cap B\cap C)=68.

Thus, the number of students who take all the three languages is 4 and the number of students who take none of the languages is 100-68 = 32.

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Step-by-step explanation:

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Step-by-step explanation:

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360 = 2·2·2·3·3·5 = 2³ · 3² · 5
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