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2 years ago

-5 x + 10 equals 55 what is X

Mathematics

2 answers:

Jobisdone [24]2 years ago

8 0

Answer:

Step-by-step explanation:

I think it’s x=-9

sladkih [1.3K]2 years ago

4 0

Answer:

$x=-9$

Step-by-step explanation:

$-5x+10=55$

Solve for x by isolating the variable. Subtract 10 from both sides:

$-5x+10-10=55-10\\\\-5x=45$

Divide both sides by -5:

$\frac{-5x}{-5}=\frac{45}{-5} \\\\x=-9$

:Done

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Answer:

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Step-by-step explanation:

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Since there are 3 pounds, and , again, each pound can fill 5 bags, she will need 15 bags.

Another way too look at it is to ask how many 1/5ths are in 3 pounds. To find this answer mathematically:

3 ÷ 1/5 = 15 because when we divide by a fraction, we need to flip it and then multiply (so 3 ÷ 1/5 is actually 3×5)

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3 years ago

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ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

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Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=9-1=8$

The Confidence interval is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and the critical values are:

$\chi^2_{\alpha/2}=20.09$

$\chi^2_{1- \alpha/2}=1.65$

And replacing into the formula for the interval we got:

$\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

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2 years ago

-5 x + 10 equals 55 what is X ​

-5 x + 10 equals 55 what is X