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tatyana61 [14]
3 years ago
10

Please help Carlos has a monthly budget of $250.00 for clothing. He spent $61.96 the first week, $52.43 the second week, and $72

.96 the third week. Using c for clothing, how much can Carlos spend on clothing during the final week of the month and still stay within budget?
Mathematics
1 answer:
gtnhenbr [62]3 years ago
6 0

Answer:

62.65

Step-by-step explanation:

250 - 61.96 - 52.43 - 72.96 - c = 0

62.65 - c = 0

62.65 = c

c = 62.65

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Read 2 more answers
Which sequence are geometric? Check all that apply
Ann [662]

Answer:

<h2>10, 7.5, 5.625, 4.21875, ...</h2><h2>160, 40, 10, 2.5, ...</h2><h2>20, 70, 245, 857.5, ...</h2><h2>5, 5.5, 6.05, 6.655, ...</h2>

Step-by-step explanation:

\text{If}\ a,\ b,\ c,\ d,\ e,\ ...\ \text{is a geometric sequence, then}\ \dfrac{b}{a}=\dfrac{c}{b}=\dfrac{d}{c}=\dfrac{e}{d}=....\\\\\#1\\\\\dfrac{7.5}{10}=0.75\\\dfrac{5.625}{7.5}=0.75\\\dfrac{4.21875}{5.625}=0.75\\\boxed{YES}\\================================\\

\#2\\\\\dfrac{40}{160}=\dfrac{1}{4}\\\dfrac{10}{40}=\dfrac{1}{4}\\\dfrac{2.5}{10}=\dfrac{1}{4}\\\boxed{YES}\\================================\\

\#3\\\\\dfrac{70}{20}=3.5\\\dfrac{245}{70}=3.5\\\dfrac{857.5}{245}=3.5\\\boxed{YES}\\================================\\

\#4\\\\\dfrac{16.5}{13}=\dfrac{165}{130}=\dfrac{33}{26}\\\dfrac{20}{16.5}=\dfrac{200}{165}=\dfrac{40}{33}\neq\dfrac{33}{26}\\\boxed{NO}\\================================\\

\#5\\\\\dfrac{5.5}{5}=1.1\\\dfrac{6.05}{5.5}=1.1\\\dfrac{6.655}{6.05}=1.1\\\boxed{YES}\\================================\\

\#6\\\\\dfrac{17.1}{16}=1.06875\\\dfrac{18.2}{17.1}=1.0643274..\neq1.06875\\\boxed{NO}

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3 years ago
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natka813 [3]

Answer: u r supposed to solve for substitution/add/subtract and ur answer should be (-2,9)

Step-by-step explanation:

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