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3241004551 [841]
3 years ago
11

On average, how many mini marshmellows are in 1 serving? Explain. 9+2x6÷2-8x5-7+124=

Mathematics
1 answer:
ad-work [718]3 years ago
5 0
The answer would be 92 for this problem 
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What is the value of x?<br><br><br><br> Enter your answer in the box.
lubasha [3.4K]

Notice that based on the diagram, all of the sides of the triangle are the same length. (The dashes on the sides of the triangle show that the sides are of congruence.) This means that the triangle is an equilateral triangle. An important thing to note about equilateral triangles is that they all have angles of 60°. All angles in equivalent triangles are 60°.


This means that we can set 7x - 3 equal to 60 to solve for x:

7x - 3 = 60

  • Set up

7x = 63

  • Add 3 to both sides

x = 9

  • Divide both sides by 7

Our answer is x = 9.

8 0
3 years ago
What is d+15-9/3+5 PLZZZZZ
zloy xaker [14]
D + 15 - 9 / 3 + 5 the answer is : d + 17
3 0
2 years ago
Find the missing information from the following relationships
Dennis_Churaev [7]

Answer:

what missing information

Step-by-step explanation:

8 0
2 years ago
Regular quadrilateral pyramid with base edge b=55 mm and lateral edge l = 7cm. Find the sum of all edges
egoroff_w [7]

Answer:

50cm or 500mm

Step-by-step explanation:

There are 4 base edges and 4 lateral edges, therefore, multiply the number for both edges by 4 and add.

Considering the fact that we were given two units of measurement, millimeters and centimeters, but we know that there are 10mm (millimeters) in a cm (centimeter) , we can just divide 55 by 10 to get 5.5.

¦

Therefore;

5.5 x 4 = 22

7 x 4 = 28

28 + 22 = 50cm

The diagram can be drawn in order to assist in answering the question.

8 0
2 years ago
Please explain the problem to me step by step​
JulijaS [17]
<h3>Solution:</h3>

\frac{4y}{9}  -  \frac{2y}{3}  = 10 \\  =  >  \frac{4y - 6y}{9}  = 10 \\  =  >  \frac{ - 2y}{9}  = 10 \\  =  > y = 10 \times  \frac{9}{ - 2}  \\  =  > y =  - 5 \times 9 \\  =  > y =  - 45

<h3>Answer:</h3>

-45

5 0
3 years ago
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