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Dmitrij [34]
4 years ago
12

if alex got a higher grade than Ethan, and Harrison got a lower grade than Ethan, than Harrison got a lower grade than Alex. Tru

e or False? Give a single counterexample if false and 2 examples if true
Mathematics
1 answer:
kirza4 [7]4 years ago
4 0

Answer:

This is true!

Step-by-step explanation:

Alex got the highest grade of the three boys. Ethan got the middle grade, and Harrison got the lowest.

Let's say that they each got a grade out of 100. These are the boys, in order, by their grade:

Alex - 100%

Ethan - 50%

Harrison - 0%

Now you see that if you take out Ethan, Alex still has a higher grade than Harrison.

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The function f(x) = x] is graphed over the interval [-6, 3]. Which translation of the graph has the domain (-3, 6]? 0 A. g(x) =
bezimeni [28]

An interval graph in graphical theory is indeed an undirected graph formed by an interval set just on true line, with a top for every interval as well as an edge between vertex v to intersections. Graph intervals and these graphs are chordal graphs and graphs that are perfect, and the further discussion can be defined as follows:

Given:

\bold{function\ f(x) = |x|}

\bold{Interval \ \[-6, 3\]}

To find:

Domain=?

Solution:

The \bold{function\ f(x) = |x|} is a graphic over the[-6,3] interval.

A<em><u> graph of the domain</u></em> [-3,6 ] is indicated mostly by the <em><u>transformation </u></em>that <em><u>horizontal shifts</u></em> to combat (h(x)=f(x-3)).

\to \bold{h(x) =f(x-3)}

            =|x-3|

Therefore, the final answer is "Option (D)".

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brainly.com/question/24161708

8 0
3 years ago
Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse
Drupady [299]

Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

a(a'(d)) = a'(a(d)) = d

Step-by-step explanation:

Given

a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

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Answer:

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tia_tia [17]

Answer:

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