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lubasha [3.4K]
3 years ago
6

Which is a simplified form of the expression -3p – 4 + 4p + 8?

Mathematics
1 answer:
miss Akunina [59]3 years ago
8 0

Answer :

hello : answer :C

Step-by-step explanation:

-3p – 4 + 4p + 8 = (-3p+4p) + (-4+8) =p+4....answer :C

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What is the volume of a cylinder with a
weeeeeb [17]

Answer:

Yes it is is 392.9 m^3

Step-by-step explanation:

Volume of cylinder is π*r^2*h, π times radius squared times height.

Since the diameter is 5.2, the radius is 2.6 (half of it). 2.6^2 = 6.76, and the height is 18.5, 6.76*18.5 = 125.06. Multiply it by pi to get 392.887577258, round it to 392.9, The volume is 392.9 cubic meters.

6 0
2 years ago
A line has a slope of Negative three-fourths and passes through the point (–5, 4). Which is the equation of the line?
balandron [24]

Answer:

y=-3/4x

Step-by-step explanation:

the form is "y=mx(+/-b). m is slope. b is y-intercept.

8 0
2 years ago
Read 2 more answers
Q8<br> The midpoint of GH is M (2,2). One endpoint is H (1,9). Find the coordinates of endpoint G.
Amanda [17]

Answer:

(3,-5)

Step-by-step explanation:

Given

M = (2,2)

H = (1,9)

Required

Determine G

This is calculated using the following midpoint formula;

M(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})

Where

(x,y) = (2,2) and (x_1,y_1) = (1,9)

Substitute these values in the formula above

(2,2) = (\frac{1 + x_2}{2},\frac{9 + y_2}{2})

Solving for x_2

2 =\frac{1 + x_2}{2}

Multiply both sides by 2

2 * 2 = 1 + x_2

4 = 1 + x_2

x_2 = 4 - 1

x_2 = 3

Solving for y_2

2 = \frac{9 + y_2}{2}

Multiply both sides by 2

2 * 2 = 9 + y_2

4 = 9 + y_2

y_2 = 4 - 9

y_2= -5

Hence, the coordinates of G is (3,-5)

4 0
2 years ago
My daughter needs help with homework.
meriva
Just find the a common denominator between the two fractions and then add across 

For example on the first one i'm going to turn each fraction into an improper fraction by multiplying the whole number by the denominator then adding that number to the numerator 

2 1/8 = 17/8
4 2/3 = 14/3

Then multiply the denominators together to get 24 - this is the common denominator (24)

Figuring out the numerator is more complex - figure out what number needs to be multiplied to the original denominator that makes it 24 - then multiply that to the numerator. Add the two products and the answer should be 163/24.

This could be dead wrong because the number next to the fraction could be multiplying in - in that case the answer is 35/12 and has a completely different set of steps.
6 0
3 years ago
Somebody please assist me here
Anettt [7]

The base case of n=1 is trivially true, since

\displaystyle P\left(\bigcup_{i=1}^1 E_i\right) = P(E_1) = \sum_{i=1}^1 P(E_i)

but I think the case of n=2 may be a bit more convincing in this role. We have by the inclusion/exclusion principle

\displaystyle P\left(\bigcup_{i=1}^2 E_i\right) = P(E_1 \cup E_2) \\\\ P\left(\bigcup_{i=1}^2 E_i\right) = P(E_1) + P(E_2) - P(E_1 \cap E_2) \\\\ P\left(\bigcup_{i=1}^2 E_i\right) \le P(E_1) + P(E_2) \\\\ P\left(\bigcup_{i=1}^2 E_i\right) \le \sum_{i=1}^2 P(E_i)

with equality if E_1\cap E_2=\emptyset.

Now assume the case of n=k is true, that

\displaystyle P\left(\bigcup_{i=1}^k E_i\right) \le \sum_{i=1}^k P(E_i)

We want to use this to prove the claim for n=k+1, that

\displaystyle P\left(\bigcup_{i=1}^{k+1} E_i\right) \le \sum_{i=1}^{k+1} P(E_i)

The I/EP tells us

\displaystyle P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) = P\left(\left(\bigcup\limits_{i=1}^k E_i\right) \cup E_{k+1}\right) \\\\ P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) = P\left(\bigcup\limits_{i=1}^k E_i\right) + P(E_{k+1}) - P\left(\left(\bigcup\limits_{i=1}^k E_i\right) \cap E_{k+1}\right)

and by the same argument as in the n=2 case, this leads to

\displaystyle P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) = P\left(\bigcup\limits_{i=1}^k E_i\right) + P(E_{k+1}) - P\left(\left(\bigcup\limits_{i=1}^k E_i\right) \cap E_{k+1}\right) \\\\ P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) \le P\left(\bigcup\limits_{i=1}^k E_i\right) + P(E_{k+1})

By the induction hypothesis, we have an upper bound for the probability of the union of the E_1 through E_k. The result follows.

\displaystyle P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) \le P\left(\bigcup\limits_{i=1}^k E_i\right) + P(E_{k+1}) \\\\ P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) \le \sum_{i=1}^k P(E_i) + P(E_{k+1}) \\\\ P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) \le \sum_{i=1}^{k+1} P(E_i)

5 0
2 years ago
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