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3 years ago

Which is a simplified form of the expression -3p – 4 + 4p + 8?

Mathematics

1 answer:

miss Akunina [59]3 years ago

8 0

Answer :

hello : answer :C

Step-by-step explanation:

-3p – 4 + 4p + 8 = (-3p+4p) + (-4+8) =p+4....answer :C

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what is the equation to seven less than the product of twice a number is greater than 5 more than the same number

postnew [5]

seven less than (-7) than the product of twice a number (2x) is greater than (>) five more than (+5) the same number (x)

2x-7>x+5
treat the > sign as an equals for now
2x-7=x+5
subtract x from both sides
x-7=5
add 7 to both sides
x=12
put the > sign back in
x>12

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3 years ago

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What is the value of the expression when h = 5? h + 7

taurus [48]

Answer:

Step-by-step explanation:

if h=5

then h+7 = 5+7 = 12

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2 years ago

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6) Triangle RST has vertices R(2,3), S(5. -1), and T(3, -4). The triangle is rotated 90° counterclockwise about the origin. Whic

Contact [7]

Answer:

T'(4, 3)

Step-by-step explanation:

The rule of 90° counterclockwise rotation about the origin:

(x, y) → (-y, x)

Apply the rule to the point T:

T(3, -4) → T'(4, 3)

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3 years ago

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A recipe calls for 2 1/2 cups of flour to make 24 cookies how many cups of flour would be required to bake 15 dozen cookies

Citrus2011 [14]

15 dozen = 180 cookies

180 ÷ 24 = 7.5

7.5 x 2.5 = 18 3/4 cups of flour

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3 years ago

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Two streams flow into a reservoir. Let X and Y be two continuous random variables representing the flow of each stream with join

zlopas [31]

Answer:

c = 0.165

Step-by-step explanation:

Given:

f(x, y) = cx y(1 + y) for 0 ≤ x ≤ 3 and 0 ≤ y ≤ 3,

f(x, y) = 0 otherwise.

Required:

The value of c

To find the value of c, we make use of the property of a joint probability distribution function which states that

$\int\limits^a_b \int\limits^a_b {f(x,y)} \, dy \, dx = 1$

where a and b represent -infinity to +infinity (in other words, the bound of the distribution)

By substituting cx y(1 + y) for f(x, y) and replacing a and b with their respective values, we have

$\int\limits^3_0 \int\limits^3_0 {cxy(1+y)} \, dy \, dx = 1$

Since c is a constant, we can bring it out of the integral sign; to give us

$c\int\limits^3_0 \int\limits^3_0 {xy(1+y)} \, dy \, dx = 1$

Open the bracket

$c\int\limits^3_0 \int\limits^3_0 {xy+xy^{2} } \, dy \, dx = 1$

Integrate with respect to y

$c\int\limits^3_0 {\frac{xy^{2}}{2} +\frac{xy^{3}}{3} } \, dx (0,3}) = 1$

Substitute 0 and 3 for y

$c\int\limits^3_0 {(\frac{x* 3^{2}}{2} +\frac{x * 3^{3}}{3} ) - (\frac{x* 0^{2}}{2} +\frac{x * 0^{3}}{3})} \, dx = 1$

$c\int\limits^3_0 {(\frac{x* 9}{2} +\frac{x * 27}{3} ) - (0 +0) \, dx = 1$

$c\int\limits^3_0 {(\frac{9x}{2} +\frac{27x}{3} ) \, dx = 1$

Add fraction

$c\int\limits^3_0 {(\frac{27x + 54x}{6}) \, dx = 1$

$c\int\limits^3_0 {\frac{81x}{6} \, dx = 1$

Rewrite;

$c\int\limits^3_0 (81x * \frac{1}{6}) \, dx = 1$

The $\frac{1}{6}$ is a constant, so it can be removed from the integral sign to give

$c * \frac{1}{6}\int\limits^3_0 (81x ) \, dx = 1$

$\frac{c}{6}\int\limits^3_0 (81x ) \, dx = 1$

Integrate with respect to x

$\frac{c}{6} * \frac{81x^{2}}{2} (0,3) = 1$

Substitute 0 and 3 for x

$\frac{c}{6} * \frac{81 * 3^{2} - 81 * 0^{2}}{2} = 1$

$\frac{c}{6} * \frac{81 * 9 - 0}{2} = 1$

$\frac{c}{6} * \frac{729}{2} = 1$

$\frac{729c}{12} = 1$

Multiply both sides by $\frac{12}{729}$

$c = \frac{12}{729}$

$c = 0.0165 (Approximately)$

8 0

3 years ago