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Alborosie
3 years ago
5

You are taking a test in science. For every 3 questions, you have 5 minutes.

Mathematics
1 answer:
Eduardwww [97]3 years ago
7 0

Answer:

50 minutes

Step-by-step explanation:

5•10

50

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26. Define a relation ∼ ∼ on R 2 R2 by stating that ( a , b ) ∼ ( c , d ) (a,b)∼(c,d) if and only if a 2 + b 2 ≤ c 2 + d 2 . a2+
Tresset [83]

Answer:

~ is reflexive.

~ is asymmetric.

~ is transitive.

Step-by-step explanation:

~ is reflexive:

i.e., to prove $ \forall (a, b) \in \mathbb{R}^2 $, $ (a, b) R(a, b) $.

That is, every element in the domain is related to itself.

The given relation is $\sim: (a,b) \sim (c, d) \iff a^2 + b^2 \leq c^2 + d^2$

Reflexive:

$ (a, b) \sim (a, b) $ since $ a^2 + b^2 = a^2 + b^2 $

This is true for any pair of numbers in $ \mathbb{R}^2 $. So, $ \sim $ is reflexive.

Symmetry:

$ \sim $ is symmetry iff whenever $ (a, b) \sim (c, d) $ then $  (c, d) \sim (a, b) $.

Consider the following counter - example.

Let (a, b) = (2, 3) and (c, d) = (6, 3)

$ a^2 + b^2 = 2^2 + 3^2 = 4 + 9 = 13 $

$ c^2 + d^2 = 6^2 + 3^2 = 36 + 9 = 42 $

Hence, $ (a, b) \sim (c, d) $ since $ a^2 + b^2 \leq c^2 + d^2 $

Note that $ c^2 + d^2 \nleq a^2 + b^2 $

Hence, the given relation is not symmetric.

Transitive:

$ \sim $ is transitive iff whenever $ (a, b) \sim (c, d) \hspace{2mm} \& \hspace{2mm} (c, d) \sim (e, f) $ then $ (a, b) \sim (e, f) $

To prove transitivity let us assume $ (a, b) \sim (c, d) $ and $ (c, d) \sim (e, f) $.

We have to show $ (a, b) \sim (e, f) $

Since $ (a, b) \sim (c, d) $ we have: $ a^2 + b^2 \leq c^2 + d^2 $

Since $ (c, d) \sim (e, f) $ we have: $ c^2 + d^2 \leq e^2 + f^2 $

Combining both the inequalities we get:

$ a^2 + b^2 \leq c^2 + d^2 \leq e^2 + f^2 $

Therefore, we get:  $ a^2 + b^2 \leq e^2 + f^2 $

Therefore, $ \sim $ is transitive.

Hence, proved.

3 0
3 years ago
Re-write the quadratic function below in Standard Form<br> y = 9(x - 1)(x + 3)
Maksim231197 [3]
Y=9(x^2+3x-x-3)
y=9(x^2+2x-3)
y=9x^2+18x-27
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3 years ago
Peter ran 4 ⅔ miles on Tuesday. On Wednesday, he ran ⅘ of this distance. How far did he run?
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Answer:

3.73333

Step-by-step explanation:

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3 years ago
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\bf \textit{arc's length}\\\\&#10;s=\cfrac{\theta \pi r}{180}\quad &#10;\begin{cases}&#10;r=radius\\&#10;\theta =angle~in\\&#10;\qquad degrees\\&#10;------\\&#10;\theta = 80\\&#10;r=26&#10;\end{cases}\implies s=\cfrac{80\cdot \pi \cdot 26}{180}
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-5(x+2)+3x= Which expression can be written in the box on the other side of the equation
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Answer:

O-2(x+5)

Step-by-step explanation:

I have to much time on my hands

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