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zvonat [6]
3 years ago
11

Which function has a range of f(x)≥7

Mathematics
1 answer:
amid [387]3 years ago
3 0

Answer:

While it's true that quadratic functions have no domain restrictions, the range is restricted because x2 ≥ 0. The correct answer is: The domain is all real numbers and the range is all real numbers f(x) such that f(x) ≥ 7.

Step-by-step explanation:

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Find the fourth point of a parallelogram given the first three (more than one correct answer is possible): (0,6), (5, -1) and (3
inysia [295]

Answer:

The fourth point of the parallelogram is one point among (-2,2), (2,10) and (8,-12).

Step-by-step explanation:

Given information: The first three vertices of parallelogram are (0,6), (5, -1) and (3,-5).

Let fourth point of the parallelogram is (a,b).

Diagonals of a parallelogram bisect each other. It means midpoint of both diagonals are same.

Midpoint formula:

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Case 1: If the point (0,6), (5, -1) and (3,-5) are consecutive, then pairs of opposite vertices are (0,6) and (3,-5), (5,-1) and (a,b).

(\frac{0+3}{2},\frac{6-5}{2})=(\frac{5+a}{2},\frac{-1+b}{2})

(\frac{3}{2},\frac{1}{2})=(\frac{5+a}{2},\frac{-1+b}{2})

On comparing both sides, we get

\frac{3}{2}=\frac{5+a}{2}

3=5+a

a=-2

\frac{1}{2}=\frac{-1+b}{2}

1=-1+b

b=2

It means the fourth point of the parallelogram is (-2,2).

Case 2: If the point (0,6), (5, -1) and (3,-5) are not consecutive, then pairs of opposite vertices are (0,6) and (5,-1), (3,-5) and (a,b).

(\frac{0+5}{2},\frac{6-1}{2})=(\frac{3+a}{2},\frac{-5+b}{2})

(\frac{5}{2},\frac{5}{2})=(\frac{3+a}{2},\frac{-5+b}{2})

On comparing both sides, we get

\frac{5}{2}=\frac{3+a}{2}

5=3+a

a=2

\frac{5}{2}=\frac{-5+b}{2}

5=-5+b

b=10

It means the fourth point of the parallelogram is (2,10).

Case 3: If the point (0,6), (5, -1) and (3,-5) are not consecutive, then pairs of opposite vertices are (5,-1) and (3,-5), (0,6) and (a,b).

(\frac{5+3}{2},\frac{-1-5}{2})=(\frac{0+a}{2},\frac{6+b}{2})

(\frac{8}{2},\frac{-6}{2})=(\frac{a}{2},\frac{6+b}{2})

On comparing both sides, we get

\frac{8}{2}=\frac{a}{2}

8=a

\frac{-6}{2}=\frac{6+b}{2}

-6=6+b

b=-12

It means the fourth point of the parallelogram is (8,-12).

5 0
4 years ago
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