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Hoochie [10]
3 years ago
12

I need Geometry help

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
3 0
Yes that is correct
answer
AAS congruence theorem
<M = <P
<MNR = <PNQ
RN = NQ
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If f(x) = 2x + 3 and g(x) = 3x - 9, find (f + g)(x).
coldgirl [10]

Answer:

5x-6

Step-by-step explanation:

f(x) = 2x + 3

g(x) = 3x - 9

f(x) + g(x) = 2x + 3  + 3x-9

               = 5x-6

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How to write 60 as a product of prime factors
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60
30 *2 
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5 * 3 * 2 * 2
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4. Consider the following graph.
AnnZ [28]

Answer:

Step-by-step explanation:

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7 0
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What is the exact circumference of a circle with a radius of 12 inches?
Anestetic [448]
We can get the circumference of any circle in terms of the radius with this formula. C = 2\pir.

Where r is the radius of the circle.

And we will use 3.14 for \pi.

Plug in all the values.

C = 2 * 3.14 * 2

C = 12.56

So, the circumference of the circle is 12.6 inches when rounded to the nearest tenth.
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3 years ago
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7.<br>(-3x³)(-2x³y⁴z)(-3z²)÷(4x³z)(-3yz) (-3xyz)​
serg [7]

Answer:

-\frac{x^2y^2}{2}

Step-by-step explanation:

We have an extremely large equation and are asked to divide it, so let's solve it step-by-step :

Remove the parenthesis to make it easier to read :

\frac{-3x^3 *2x^3y^4z *3z^2}{4x^3z*3yz*3xyz}

Multiply the numerators :

\frac{-18x^6y^4z^3}{4*3*3x^3yyzzz}

Multiply the denominators :

\frac{-18x^6y^4z^3}{36x^4y^2z^3}

Apply the negative rule :

-\frac{18x^6y^4z^3}{36x^4y^2z^3}

Cancel the common factor which is 18 :

-\frac{x^6y^4z^3}{2x^4y^2z^3}

Apply the addition exponent rule :

\frac{y^4z^3x^{6-4} }{2y^2z^3}

Subtract :

\frac{x^2y^4z^3 }{2y^2z^3}

Apply the rule for y :

\frac{x^2y^{4-2} z^3 }{2z^3}

Subtract :

\frac{x^2y^2z^3 }{2z^3}

Cancel the common factor of z^3 :

-\frac{x^2y^2}{2}

5 0
3 years ago
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