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topjm [15]
3 years ago
7

Helpmeet with 'this question please

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
6 0
A) is 5 months
b) is option 1 difference of 40

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What is a product of 2 numbers
I am Lyosha [343]
The product of a number is its multiplication answer. so the product of 3x3 would be 9.
6 0
3 years ago
Les bought 6 pairs of shorts for s dollars each and a blazer that cost three times as much as the pair of shorts. He spent a tot
cestrela7 [59]
6 pairs of shorts, for a
"s" dollars. A blazer costs 3 times as much, she bought one. The total was 139.50

6s + 3(6s) = 139.50
6s + 18s = 139.50
25s = 139.50 Divide everything by 25,
s = 5.58, which is how much the shorts were. Now for the blazers ;

It said they were three times the cost of shorts, if shorts are 5.58, it is 3*5.58.
3s
3(5.58)
16.74

The blazer cost 16.74
8 0
3 years ago
Plz answer for a brainly, ill give u brainliy and 100 points
bezimeni [28]

Answer:

what is this

Step-by-step explanation:

what's the question

5 0
3 years ago
Read 2 more answers
Find an equilvalent ratio 12/10
lisabon 2012 [21]
Divide by 2/2
6/5
If you need it converted to an improper fraction it would be 1 1/5
6 0
3 years ago
In a race in which eleven automobiles are entered and there are no ties, in how many ways can the first three finishers come in?
viva [34]

Answer:

990 ways

Step-by-step explanation:

The total number of automobiles we have is 11.

Now, what this means is that for the first position , we shall be selecting 1 out of 11 automobiles, this can be done in 11 ways( 11C1 = 11!/(11-1)!1! = 11!/10!1! = 11 ways)

For the second position, since we have the first position already, the number of ways we can select the second position is selecting 1 out of available 10 and that can be done in 10 ways(10C1 ways = 10!9!1! = 10 ways)

For the third position, we have 9 automobiles and we want to select 1, this can be done in 9 ways(9C1 ways = 9!/8!1! = 9 ways)

Thus, the total number of ways the first three finishers come in = 11 * 10 * 9 = 990 ways

8 0
3 years ago
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