Let
S = cost of skateboard
B = cost of bicycle.
We are given that skateboard and bicycle cost $199.00. We can write this algebraically as
S + B = 199 (Equation 1)
We also know that the skateboard costs $51.00 less than the bicycle. We write this algebraically as
S = B - 51 (Equation 2)
Substituting Equation 2 in Equation 1, we get
S + B = 199
--> (B - 51) + B = 199
--> B - 51 + B = 199
--> 2B - 51 = 199
--> 2B - 51 + 51 = 199 + 51
--> 2B = 250
--> 2B / 2 = 250 / 2
--> B = 125
Now substituting this value B = 125 in Equation 2 gives
S = B - 51 = 125 - 51 = 74
So S = 74 and B = 51 implies that the skateboard costs $74 and the bicycle costs $125.
Answer:
False
Step-by-step explanation:
Therefore, false.
Answer:
c = 12
Step-by-step explanation:
3(c - 4) = 4(c - 6)
Use the distributive property on each side.
3c - 12 = 4c - 24
Now you need the terms with c on the left side and the numbers on the right side. Subtract 4c from both sides. Add 12 to both sides.
3c - 4c - 12 + 12 = 4c - 4c - 24 + 12
Combine like terms on each side.
-c = -12
Multiply both sides by -1.
c = 12
Answer:
36m+ 25
Step-by-step explanation:
