Can some please help me
1 answer:
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Answer:
to solve you would first need to convert them from mixed numbers to improper fractions. You can do this by multiplying the denominator with the whole number and then adding the numerator. Then you should make sure that the denominators are the same. You can do this by first finding a number that they will both multiply into. In this example it is 12. And when changing the denominator you must apply it to the numerator. So if you multiplied the denominator by 3 then you must multiply the numerator by 3. After you can just minus the numerators. However remember to keep the denominator the same. Then you can change it back into a mixed number by dividing the numerator by the denominator and having that whole number on the side of the fraction . lets say it is
then you would divide 13 by 6 which is 2 and a decimal and then minus the number that is multiplied by the numerator and it will give a number that is smaller than the denominator and then it would become
.
Step-by-step explanation:
1) Change the fractions to improper fractions.
2) Change the denominator to a common denominator.
3) Minus the Numerators.
4) Changing it to a mixed number
Answer: The area of the regions covered by grass is approximately 313.375 sq ft.
Step-by-step explanation:
Given: A company is building a new park in the shape of a circle with a 25 ft diameter.
Then radius =
Required area = Area of circle - Area of rectangle + Area of triangle
Formula: Area of circle =
Area of rectangle = length x width
Area of triangle = 0.5 x base x height
Area of circle =
Area of rectangle = 20 ft x 10ft = 200 ft²
Area of triangle = 0.5 x 7 x 6.5 = 22.75 ft²
Required area = 490.625 -200+22.75 = 313.375 ft²
Hence, The area of the regions covered by grass is approximately 313.375 sq ft.
Answer:
See the proof below.
Step-by-step explanation:
For this case we just need to apply properties of expected value. We know that the estimator is given by:
And we want to proof that
So we can begin with this:
And we can distribute the expected value into the temrs like this:
And we know that the expected value for the estimator of the variance s is , or in other way
so if we apply this property here we have:
And we know that so using this we can take common factor like this:
And then we see that the pooled variance is an unbiased estimator for the population variance when we have two population with the same variance.