Can some please help me
1 answer:
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From my own solution, my answer is closest to D<span>. 1951 yd; 27°
</span><span>
The boat is 1951 yards away from the observer in tower B. The angle of depression to the boat from Tower B is 27</span>°.<span>
Pls. see my attachment.
In it I divided the big triangle into two small right triangles.
I solved for the common leg of the right triangles by using sin theta formula. sin </span>θ = opposite / hypotenuse
<span>
sin 35</span>° = opposite / 1538 yd
<span>sin 35</span>° * 1538 yd = opposite
<span>882.16 yd = opposite
From there, I used the Pythagorean theorem to solve for the missing side which is part of the 3,000 yd measure.
I got the measure of 1,259.86 yards. The remaining measure of 1,740.14 is the side of the other right triangle.
Still using Pythagorean Theorem, I used the measurement of the known side of the 2nd right triangle to solve for its hypotenuse which was 1,950.97 or 1,951 yards.
With regards to the angle of depression, I used this formula:
tan(y) = opposite / adjacent
tan(y) = 1538 yd / 3000 yd
tan(y) = 0.513
y = 0.513/tan
y = 27.14</span>°<span>
</span>
</span><span>
The boat is 1951 yards away from the observer in tower B. The angle of depression to the boat from Tower B is 27</span>°.<span>
Pls. see my attachment.
In it I divided the big triangle into two small right triangles.
I solved for the common leg of the right triangles by using sin theta formula. sin </span>θ = opposite / hypotenuse
<span>
sin 35</span>° = opposite / 1538 yd
<span>sin 35</span>° * 1538 yd = opposite
<span>882.16 yd = opposite
From there, I used the Pythagorean theorem to solve for the missing side which is part of the 3,000 yd measure.
I got the measure of 1,259.86 yards. The remaining measure of 1,740.14 is the side of the other right triangle.
Still using Pythagorean Theorem, I used the measurement of the known side of the 2nd right triangle to solve for its hypotenuse which was 1,950.97 or 1,951 yards.
With regards to the angle of depression, I used this formula:
tan(y) = opposite / adjacent
tan(y) = 1538 yd / 3000 yd
tan(y) = 0.513
y = 0.513/tan
y = 27.14</span>°<span>
</span>
Answer:
Step-by-step explanation:
We have been given that when a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a rate of 0.7 meters per hour. We are asked to find the approximate radius of tank in meters.
We will use volume of cylinder formula to solve our given problem as:
, where,
r = Radius,
h = Height of cylinder.
Since the level of water in the tank rises at a rate of 0.7 meters per hour, so height of cylinder would be meters at
.
Upon substituting these values in above formula, we will get:
Now, we will take positive square root of both sides as radius cannot be negative.
Therefore, radius of tank would be approximately square root of 10 m.