You use the quadratic formula:
2x {}^{2} - 3x = 5
2x {}^{2} - 3x - 5 = 0
x = \frac{3 + - \sqrt{9 -4(2)( - 5)}}{2 \times 2}
x = \frac{3 + - \sqrt{49} }{4}
x = \frac{3 + 7}{4} \: and \: x = \frac{3 - 7}{4}
x = \frac{5}{2} \: and \: x = - 1
Answer:
186.5 + 2x
Step-by-step explanation:
First, radify 25. Luckily it's a perfect square so it will be 5.
Second, divide within the parentheses. You're expression should look like this.
(93-5+x+42/8)2
Divide 42/8. The decimal form would be 5.25, while the fraction should be 5 1/4.
Third, solve within the parentheses from left to right. Right now you're expression should look like this:
(93-5+x+5.25)2
Add all like terms
93-5+5.25=93.25
Fourth, multiply. Right now the expression should look like this:
(93.25 + x) 2
186.5 + 2x
Answer: the second option
explanation: below
Answer:
First, let's define an arithmetic sequence:
In an arithmetic sequence, the difference between any two consecutive terms is always the same.
Then we can write it in a general way as:
aₙ = a₁ + (n - 1)*d
where:
aₙ is the n-th term of the sequence.
d is the constant difference between two consecutive terms.
a₁ is the initial term of our sequence.
Now in this case we know that the first terms of our sequence are:
84, 77, ...
Then we know the initial term of our sequence:
a₁ = 84.
And the value of d can be calculated as:
d = a₂ - a₁ = 77 - 84 = -7
Then the general way of writing this sequence is:
aₙ = 84 + (n - 1)*(-7)
And the recursion relation is:
aₙ = aₙ₋₁ - 7
So for the n-th term, we must subtract 7 of the previous term.
