Answer:
The volume of water needed=0.86 liters
Explanation:
Step 1: Form an equation
The equation can be expressed as follows;
(Ac×Va)+(Wc+Vw)=Fc(Va+Vw)
where;
Ac=initial concentration of antifreeze
Va=volume of antifreeze in liters
Wc=concentration of water
Vw=volume of the water in liters
Fc=final concentration of the antifreeze
This expression can be written as;
(concentration of antifreeze×volume of antifreeze in liters)+(concentration of water×volume of the water)=final concentration of the antifreeze(volume of antifreeze in liters+volume of the water in liters)
In our case;
Ac=45%=45/100=0.45
Va=3 liters
Wc=0
Vw=unknown
Fc=35%=35/100=0.35
Replacing;
(0.45×3)+(0×Vw)=0.35(3+Vw)
1.35=1.05+0.35 Vw
0.35 Vw=1.35-1.05
0.35 Vw=0.30
Vw=0.3/0.35=0.86
Vw=0.86 liters
The volume of water needed=0.86 liters
17.8% is the irr for the project if the cost of capital is 12%. IRR <span>is the interest rate at which the net present value (NPV) of all the cash flows (both positive and negative) from a project or investment equal tgo zero.</span> IRR<span> calculations rely on the same </span>formula<span> as NPV does. To </span>calculate IRR <span>using the </span>formula<span>, one would set NPV equal to zero and </span>solve<span> for the discount rate (r), which is the </span>IRR. <span>Multiply the net cash flow for each period by its discount factor to obtain its present value. Sum the present values of each cash flow to </span>calculate<span> the </span>NPV. Find the IRR<span>, the discount rate, that makes the </span>NPV<span> zero.</span>
Answer:
"Stop-loss order" is the right answer.
Explanation:
According to the question,
Purchase price,
= $50
Current selling price,
= $80
Current gains,
= $30
- Investors begin to give their earnings if somehow the market capitalization begins to fall beneath $80. In advance to minimize this, we need to set a purchase requisition of $80 for stop-loss.
- So whenever the market decreases beyond $80, with us investments are traded, and thereby the existing profits of $30 have been safeguarded.
Thus, the above is the correct explanation.
Answer:

This profit equation is an equation of a parabola that opens downward (Since A=-0.07<0) and has its vertex at

Thus, revenue is maximized when x=250 hundred units. At this quantity maximum profit is
P(250)=3800.23 hundred dollars
b. Profits are maximised at x=250 hundred units. The per unit price at this is,

Answer:
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