Answer:
They need to buy 6 pairs of uniform pants so that they pay the same amount for their purchases
Step-by-step explanation:
Let x be the no. of pairs of uniform pants for which the total cost in both the cases will be same.
Case 1:
Cost of 1 pairs of uniform pants = $17.95 each
Cost of x pairs of uniform pants = $17.95x
Cost of sweater = $24.
Total cost = 24+17.95x
Case 2:
Cost of 1 pairs of uniform pants = $18.95
Cost of x pairs of uniform pants = $18.95x
Cost of sweater = $18
Total cost = 18+18.95x
ATQ




Hence they need to buy 6 pairs of uniform pants so that they pay the same amount for their purchases
Answer:
when input = n, Output = 4n
Step-by-step explanation:
Output = k(input)
Where,
k = constant
Find k When output = 8 and input = 2
Output = k(input)
8 = k(2)
8 = 2k
k = 8/2
k = 4
Find k When output = 28 and input = 7
Output = k(input)
28 = k(7)
28 = 7k
k =28/7
k = 4
Find output when input = n
Output = k(input)
= 4(n)
= 4n
Output = 4n
when input = n, Output = 4n
Answer: 48
Step-by-step explanation: 10% of 480 would be 48 because your finding 10% of 480. for example: 10% of 100 would be ten because if you multiplied 10 times 10 it would be 100.