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2 years ago

What are the values of x and y?

Mathematics

1 answer:

d1i1m1o1n [39]2 years ago

8 0

Answer:

Step-by-step explanation:

y is the value obtained from 4 and 12

y^2 = 4 * 12 Combine

y^2 = 48 Square root both sides.

√y^2 = √48

y = √(3 * 4 * 4)

y = 4√3

Use the Pythagorean Theorem to obtain x

x^2 = y^2 + 4^2

x^2 = 48 + 16

x^2 = 64 Take the square root of both sides

√x^2 = √64

x = 8

Answer

x = 8
y = 4√3

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Whixh statement is true about the graphs of the functions shown below?

Nata [24]

Answer:

Step-by-step explanation:

Since G(0) = g(0) = 20, the parabolic graphs of these functions share a y-intercept: (0, 20).

Completing the square puts these equations into vertex form, which simplifies comparisons of the graphs:

G(x) = 2x^2 - 12x + 20 becomes

2(x^2 - 6x + 9 - 9) + 20, or

2(x - 3)^2 - 18 + 20, or 2(x - 3)^2 + 2. Comparing this result to

a(x - h)^2 + k, we see that the vertex is located at (3, 2).

Going through the same process for g(x) 2x^2+12x+20, we get:

g(x) = 2(x + 3)^2 + 2, whose vertex is at (-3, 2).

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3 years ago

Brainliest to Correct answer! Identify the relationship described below.

kenny6666 [7]

Answer:

Commenalism

Step-by-step explanation:

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7 0

3 years ago

Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).

NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

$1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}$

Now, differentiate to obtain

$\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}$

$=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}$

To obtain the required form, extract a factor in both the numerator and denominator:

$\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)$

3 0

3 years ago

From a shipment of 400 light-bulbs, a sample of 80 was selected at random and tested. If 32 light-bulbs in the sample were found

denis-greek [22]

80 x 5 = 400
32 x 5 = 160
so you have about 160 <span>defective bulbs</span>

4 0

3 years ago

What is the solution to the system of linear equations below?<br> - 2x + 5y<br> 30

avanturin [10]

Answer: Infinite solutions

Step 1: Turn this into y=Mx+b form

The current equation is—

-2x+5y=30

Since we want to get y alone on the left side, let’s add 2x on both sides

-2x+5y=30
+2x +2x
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5y=2x+30

Step 2: Again, trying to get y alone, we need to divide 5 on both sides

5y=2x+30
/5 /5 /5
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y=2/5x+6

Step 3: Now that we know how to find y, substitute that in where y is in the equation

-2x + 5(2/5x+6) = 30
-2x + 2x + 30 = 30
30=30

Seeing that you cannot get a specific answer for y when solving, there is an infinite number of solutions

Hope this is right and it helps comment below for more questions :)

5 0

3 years ago