We will use the following law of indices (or 'index law') to check each pair of expression
![x^{ \frac{m}{n}} = ( \sqrt[n]{x} )^{m}](https://tex.z-dn.net/?f=%20x%5E%7B%20%5Cfrac%7Bm%7D%7Bn%7D%7D%20%3D%20%28%20%5Csqrt%5Bn%5D%7Bx%7D%20%29%5E%7Bm%7D%20)
With fractional power, the denominator is the root and the numerator is the power of the term. When the denominator is 2, we usually only write the normal square symbol (√). Denominator other than 2, we usually write the value of the root, for example, the cubic root ∛
Option A - Incorrect

should equal to
Option B - Correct
does equal to

Option C - Incorrect

should equal to

Option D - Incorrect

should equal to
Answer:
They are 53, 55, 57, 59 and 61.
Step-by-step explanation:
We can write the integers as x, x+2, x+4, x+6 and x+8, so
x + x + 2 + x + 4 + x + 6 + x + 8 = 285
5x + 20 = 285
5x = 265
x = 53.
The answer is: Substitution property of equality.
The explanation is shown below:
1. To solve this problem you must apply the proccedure shown below:
2. When you clear the variable x from the first equation, and subtitute it into the second equation, you obtain:
<span>3x−2y=10
x=(10+2y)/3
4x−3y=14
</span>4[(10+2y)/]−3y=14
<span> y=-2
3. When you subsitute y=-2 into the first equation and clear the x, you have:
x=2
</span>
a square as the distance between the lengths and widths are 3