Answer:
B. segment AG is congruent to segment OL
Step-by-step explanation:
I assume you're supposed to establish the identity,
cos(A) cos(2A) cos(4A) = 1/8 sin(8A) / sin(A)
Recall the double angle identity for sine:
sin(2<em>x</em>) = 2 sin(<em>x</em>) cos(<em>x</em>)
Then you have
sin(8A) = 2 sin(4A) cos(4A)
sin(8A) = 4 sin(2A) cos(2A) cos(4A)
sin(8A) = 8 sin(A) cos(A) cos(2A) cos(4A)
==> sin(8A)/(8 sin(A)) = cos(A) cos(2A) cos(4A)
as required.
The answer is 4/8 because half of 16 is 8 and half of 8 is 4, therefore they are equivalent
Answer:
14 = rounded 15
Step-by-step explanation:
What grade r u in?
And what time is where u r?
x = 3 - (3×6) + 2. We perform the operation in the bracket first.
x = 3 - 18 + 2
x = -15 + 2 = 2 -15 = -13
x = -13
