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3 years ago

12

Segment AB is dilated from the origin to create segment A prime B prime at A' (0, 6) and B' (6, 9). What scale factor was segmen

t AB dilated by?
1/2

2

3

4

1 answer:

Llana [10]3 years ago

7 0

2 is the answer of the question

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Find equations of both the tangent lines to the ellipse x^2 + 4y^2 = 36 that pass through the point (12, 3).y = (smaller slope)y

Bingel [31]

Answer:

x+y=15

Step-by-step explanation:

Given equation of $x^2+4y^2=36$

Differentiating both side $2x+8y\frac{dy}{dx}=0$

$\frac{dy}{dx}=\frac{-x}{4y}$

It passes through the point (12,3) so

$\frac{dy}{dx}=\frac{-12}{4\times 3}=1$

So equation of tangent passing through (12,3) is

$y-12=-1(x-3)$ as $y-y_1=-m(x-x_1)$

So x+y =15 will be the equation of tangent which passes though the point (12,3)

5 0

3 years ago

What are the correct answers to this geometry question?

Maru [420]

Answer:

Ti = 5

AT = 6

Kt = 10

Ai = 11

ke = 19

ae = 15

Step-by-step explanation:

6 0

3 years ago

I NEED A LOT OF HELP PLEASE! I WILL FAIL IF IT DOESNT GET DONE!

Anna35 [415]

In order to solve for this, we need to find the volumes of both the cylinder and cone described.

In order to find the area of the cylinder:
We use the equation V= $\pi r^{2} h$
So, V= $\pi 6^{2}16$
The volume of the cylinder is therefore approximately <span>1809.56 $m^{3}$

For the cone:
V= $\pi r^{2} \frac{h}{3}$
So, V= $\pi 6^{2} \frac{3}{3}$
Thus, the volume of the cone is 113.1 $m^{3}$

We add these volumes together to derive the solution, which is 1922.66 $m^{3}$ </span>

5 0

3 years ago

HELP PLEASE!!!!!!!!!!!

emmainna [20.7K]

Answer:

Part 1) $y=-x^{2}$ ---> Translated up by 1 units

Part 2) $y=x^{2}+1$ ---> Reflected across the x-axis

Part 3) $y=-(x+1)^{2}-1$ ---> Translated left by 1 unit

Part 4) $y=-(x-1)^{2}-1$ ----> Translated right by 1 unit

Part 5) $y=-x^{2}-1$ ----> Reflected across the y-axis

Part 6) $y=-x^{2}-2$ ----> Translated down by 1 unit

Step-by-step explanation:

we know that

The parent function is

$y=-x^{2}-1$ ----> this is a vertical parabola open downward with vertex at (0,-1)

<em>Calculate each case</em>

Part 1) Translated up by 1 unit

The rule of the translation is

(x,y) -----> (x,y+1)

so

(0,-1) ----> (0,-1+1)

(0,1) ----> (0,0) ----> the new vertex

The new function is equal to

$y=-x^{2}$

Part 2) Reflected across the x-axis

The rule of the reflection is

(x,y) -----> (x,-y)

so

(0,-1) ----> (0,1) ----> the new vertex

The new function is equal to

$y=x^{2}+1$

Part 3) Translated left by 1 unit

The rule of the translation is

(x,y) -----> (x-1,y)

so

(0,-1) ----> (0-1,-1)

(0,1) ----> (-1,-1) ----> the new vertex

The new function is equal to

$y=-(x+1)^{2}-1$

Part 4) Translated right by 1 unit

The rule of the translation is

(x,y) -----> (x+1,y)

so

(0,-1) ----> (0+1,-1)

(0,1) ----> (1,-1) ----> the new vertex

The new function is equal to

$y=-(x-1)^{2}-1$

Part 5) Reflected across the y-axis

The rule of the reflection is

(x,y) -----> (-x,y)

so

(0,-1) ----> (0,-1) ----> the new vertex

The new function is equal to

$y=-x^{2}-1$

Part 6) Translated down by 1 unit

The rule of the translation is

(x,y) -----> (x,y-1)

so

(0,-1) ----> (0,-1-1)

(0,1) ----> (0,-2) ----> the new vertex

The new function is equal to

$y=-x^{2}-2$

3 0

3 years ago

The number of hours per week that the television is turned on is determined for each family in a sample. The mean of the data is

katovenus [111]

Answer:

$200\ families$

Step-by-step explanation:

Already, we are given 12% of our sample size as 24.

To find the sample size, we equate to find 100%.

Let sample size be denoted by $t$

$If\ 12\%=24\\100\%=t\\t=\frac{100\%\times24}{12\%}\\=200$

Hence, the sample has 200 families.

7 0

3 years ago