Answer:
The probability of founding exactly one defective item in the sample is P=0.275.
The mean and variance of defective components in the sample are:

Step-by-step explanation:
In the case we have a lot with 3 defectives components, the proportion of defectives is:

a) The number of defectives components in the 5-components sample will follow a binomial distribution B(5,0.075).
The probability of having one defective in the sample is:

b) The mean and variance of defective components in the sample is:

The Chebyschev's inequality established:

Answer:
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Step-by-step explanation:
Answer:
x1 = t, x2 = -t and x3 = 0
Step-by-step explanation:
Given the system of equation
x1 + x2 + x3 = 0 .... 1
x1 + x2 + 9x3 = 0 .... 2
Subtract both equation
x3 - 9x3 = 0
-8x3 = 0
x3 = 0
Substitute x3 = 0 into equation 1
x1 + x2 + 0 = 0
x1+x2 = 0
x1 = -x2
Let t = x1
t = -x2
x2 = -t
Hence x1 = t, x2 = -t and x3 = 0
Answer:
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