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sertanlavr [38]
3 years ago
12

MATH 30 POINTS WILL GIVE BRAINLIEST help please

Mathematics
1 answer:
natulia [17]3 years ago
3 0

The fundamental behavior that's important here is that, as t gets arbitrarily large, a^t becomes smaller (decays) if |a| and larger (grows) if |a|>1.

100\left(1-\dfrac12\right)^t=100\left(\dfrac12\right)^t\implies\dfrac12

0.1(1.25)^t\implies1.25>1\implies\text{growth}

426(0.98)^t\implies0.98

2050\left(\dfrac12\right)^t\implies\text{decay}

\left((1-0.03)^{1/2}\right)^{2t}=0.97^t\implies0.97

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