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Advocard [28]
4 years ago
6

John and 4 friends are going out for pizza for lunch. They split one pizza and 5 large drinks. The pizza cost $12.00. After usin

g a $5.00 gift certificate, they spend a total of $14.25. Write an equation to model this situation, and find the cost of one large drink.
Mathematics
1 answer:
m_a_m_a [10]4 years ago
4 0

well if the pizza costs $12.00 then that leaves $2.25

$14.25-$12.00=$2.25

and then take $2.25 and devide it by 5 for the amout each soda costs

$2.25/5=$0.45

each soda costs $0.45

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Which equation can be used to solve for x in the following diagram? *BRAINLIEST*
natita [175]

Answer:

D

Step-by-step explanation:

This is a 90 degree angle

90-35=55

X=11

35+5x=90

-35. -35

5x=55

Divide both sides by 5

X=11

5 0
3 years ago
What is (f - g)(x)?<br>f(x) = 5x<br>g(x) = 3x2 - 8x​
erma4kov [3.2K]

Answer:

(5x)-(3x^2-8x)=-3x^2+13x

Step-by-step explanation:

(f-g)(x)=f(x)-g(x)

Using this, we can subtract and find the answer.

(5x)-(3x^2-8x)=-3x^2+13x

6 0
3 years ago
HELP please! ‍♂️<br><br> Last one is 0.5 &lt; x &lt; 1.5<br><br> And none
Ket [755]

1.5 is lesser than 0.5. Oh, wait nevermind I meant to say -1.5 is lesser than 0.5

3 0
3 years ago
wo point charges lie on the $x$ axis. A charge of +6.24 $\mu C$ is at the origin, and a charge of -9.55 $\mu C$ is at $x$ = 12.0
Andreyy89

Answer:

E_n=34,467,075.42\ N/C

Step-by-step explanation:

<u>Electric Field</u>

The electric field produced by a point charge Q at a distance d is given by

\displaystyle E=K\cdot \frac{Q}{d^2}

Where

K = 9\cdot 10^9\ Nw.m^2/c^2

The net electric field is the vector addition of the individual electric fields produced by each charge. The direction is given by the rule: If the charge is positive, the electric field points outward, if negative, it points inward.

Let's calculate the electric fields of each charge at the given point. The first charge q_1=+6.24\mu C=6.24\cdot 10^{-6}C is at the origin. We'll calculate its electric field at the point x=-3.85 cm. The distance between the charge and the point is d=3.85 cm = 0.0385 m, and the electric field points to the left:

\displaystyle E_1=9\cdot 10^9\cdot \frac{6.24\cdot 10^{-6}}{0.0385^2}

E_1=37,888,345.42\ N/C

Similarly, for q_2=-9.55\mu C=-9.55\cdot 10^{-6}C, the distance to the point is 12 cm + 3.85 cm = 15.85 cm = 0.1585 m. The electric field points to the right:

\displaystyle E_2=9\cdot 10^9\cdot \frac{9.55\cdot 10^{-6}}{0.1585^2}

E_2=3,421,270\ N/C

Since E1 and E2 are opposite, the net field is the subtraction of both

E_n=37,888,345.42\ N/C-3,421,270\ N/C

\boxed{E_n=34,467,075.42\ N/C}

6 0
4 years ago
What is the volume of this triangular prism?
sweet-ann [11.9K]

Answer:

V=5,676.16cm^3

Step-by-step explanation:

The volume of a triangular prism is defined by the formula:

V=(area-of-base)*(length)

In this case the base is triangular and the area of a triangle is: A=\frac{1}{2}(base)*(height)

Then the volume is:

V=\frac{1}{2}(base*height*length)

Now we have to replace with the given values:

V=\frac{1}{2}(22.4cm*18.1cm*28cm)\\\\V=\frac{1}{2}(11,352.32cm^3)\\\\V=5,676.16cm^3

Then the correct answer is the third option.

V=5,676.16cm^3

7 0
3 years ago
Read 2 more answers
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