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mixas84 [53]
3 years ago
15

Asking this question again because I need help! what is the surface area of the triangular prism

Mathematics
1 answer:
ElenaW [278]3 years ago
5 0

Answer:

Surface area of the triangular prism is 469 inch^2

Step-by-step explanation:

The surface area of the triangular prism is

Area of the two triangular faces + Area of the three rectangular faces

Area of the prism:

                          = 2(1/2*11*7)+(14*11)+(14*9)+(14*8)\\\\                      = 77+154+126+112\\\\                       = 469 inch^2

The area of the triangular prism is 469 inch^2

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Illusion [34]

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The Correct choice is :

  • RT is an altitude of Triangle QRS
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The graph shown models a linear relation. Use the graph to answer the following questions. The two known points are (0, -3) and
Lady_Fox [76]

9514 1404 393

Answer:

  1. 3
  2. -1

Step-by-step explanation:

1. The value can be read from the graph. At 3 units to the right of the vertical axis, the line is 3 units above the horizontal axis. The independent variable has a value of 3 at that point.

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2. The dependent variable has a value of -5 at the next grid line just below the bottom of the graph shown. The value of the independent variable is -1 at that point.

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3 years ago
Solve for x.
DerKrebs [107]

Answer:

Step-by-step explanation:

Remark

They are asking you to combine like terms. The total should be 180.

Givens

2 angles

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Total 180

Solution

8x - 3 + 4x + 3 = 180        The threes cancel. So add what's left. They are of opposite signs, so they cancel.

12x = 180                           Divide both sides by 12

12x/12 = 180 /12                        

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3 0
2 years ago
Read 2 more answers
A company produces a certain product, and each unit of this product may have 3 different types of defects. Let Di, D2,Ds represe
Stella [2.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a) 0.88

b) 0.02

c) 0.01

d) 0.99

Step-by-step explanation:

Step one: State the given parameters

            P(D_{1} ) = 0.12                                   P(D_{2} ) = 0.07

           P(D_{3} ) = 0.05                                    P (D_{1} U D_{2} ) = 0.13

          P(D_{1}n D_{2}n D_{3}) = 0.01                        P(D_{1} U D_{3}) = 0.14

Step 2 : Obtain the probability that a unit does not have a type 1 defect

         P(\frac{}{D_{1} }) =  1 -P(D_{1} )

                    = 1 - 0.12

                    = 0.88  

Step 3 : Obtain the probability that a unit has both type 2 and 3 defect?

          The probability of the unit having both type 2 and type 3 defect is denoted as P(D_{2} n D_{3} )

   This is calculated as

                    P(D_{2}n D_{3}) =P(D_{2} ) + P(D_{3}) - P(D_{2} U D_{3})\\\\                          = 0.07 + 0,05 - 0.13

                    =   0.02

Therefore P(D_{2} n D_{3} ) = 0.02

Step 4 : Obtain the probability that the unit has both a type 2 and type 3 ,but not a type 1 defect

                  Let P(\frac{}{D_{1}} n D_{2} n D_{3} ) denote the  probability that the unit has both a type 2 and type 3 ,but not a type 1 defect.

This can be calculated as follows :

                      P(\frac{}{D_{1}} n D_{2} n D_{3} ) = P(D_{2} n D_{3}) - P(D_{1} n D_{2}nD_{3})

                                               =   0.02 - 0.01

                                               =  0.01

Step 4 : Obtain the probability that a unit has at most two defects

               P(at most 2 defects)  = 1 - P(all three defects)

                                                  = 1- P(D_{1} n D_{2}nD_{3})

                                                  =  1 - 0.01

                                                  = 0.99

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3 years ago
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