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Lemur [1.5K]
3 years ago
10

Arte these examples of commutative, Associative or Distributive property?I

Mathematics
1 answer:
valentinak56 [21]3 years ago
8 0

Answer:

both these equations are the examples of associative property.

#1 is the example of associative property with respect to multiplication.

#2 is the example of associative property with respect to addition.

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The diameter of a circle is 4 cm. Which equation can be used to find its circumference?
Leya [2.2K]

Answer:

pi times 4

Step-by-step explanation:

Circumference: pi times diameter (pi)(d) or pi times 2 times the radius (pi)(2r)

5 0
3 years ago
Read 2 more answers
Help!!! please what's is the figure​
S_A_V [24]

Hello from MrBillDoesMath!

Answer:

108 cm^2

Discussion:

The area of the logo  =

area of Trapezoid on top (I)  + area of triangle on bottom (II)

I  = (1/2) h ( b1 + b2)            h = altitude, b1, b2 = bases

  = (1/2)  6  ( 6  + 12)

  = (1/2) 6 ( 18)

  = 54

II  = (1/2) b h

   = (1/2) (12) ( 15 - 6)               => altitude of triangle = 15 - 6 NOT (1/2) 15

   =  54

I + II= 54 + 54 = 108

Thank you,

MrB

3 0
3 years ago
Read 2 more answers
26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
2 years ago
What is the solution to 3x + 2.4 ≥ 3.0​
vichka [17]
3x _> 3.0 - 2.4
= 3x _> 3/5
= 1/5
7 0
3 years ago
Read 2 more answers
Find X. Round to the nearest tenth if necessary.
storchak [24]

Answer:

3.2

Step-by-step explanation:

If there are 2 secont lines intersecting inside a circle like the picture shown, then the theorem tells us that <em>"the product of 2 segments of one secant line is equal to the product of 2 segments of other secant line"</em>

<em></em>

Thus, we can say that:

x * 10 = 8 * 4

10x = 32

x = 32/10

x = 3.2

3 0
3 years ago
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