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Evgesh-ka [11]
3 years ago
13

Please answer both thank you​

Mathematics
1 answer:
jeyben [28]3 years ago
7 0

Answer:

7.

Solution given;

male=15

female=27

1st term=5*3

2nd term=3*3*3

now

Highest common factor=3

So

<u>The</u><u> </u><u>maximum</u><u> </u><u>number</u><u> </u><u>of</u><u> </u><u>groups</u><u> </u><u>that</u><u> </u><u>the</u><u> </u><u>teacher</u><u> </u><u>can</u><u> </u><u>make</u><u> </u><u>is</u><u> </u><u>3</u><u>.</u>

<u>and</u><u> </u><u>each</u><u> </u><u>team</u><u> </u><u>contains</u><u> </u><u>5</u><u> </u><u>male and</u><u> </u><u>9</u><u> </u><u>female</u><u>.</u>

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