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2 years ago

Please answer both thank you

Mathematics

1 answer:

jeyben [28]2 years ago

7 0

Answer:

Solution given;

male=15

female=27

1st term=5*3

2nd term=3*3*3

now

Highest common factor=3

The maximum number of groups that the teacher can make is 3.

and each team contains 5 male and 9 female.

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Danielle and Emilia brought apples, bananas, and oranges to a fruit sale.

lilavasa [31]

Answer:

26 apples

Step-by-step explanation:

bananas, b= $0.50

oranges, o= $0.75

apples, a = $0.75

Total fruit sold = 50

Total Earned = $33.50

b + o + a = 50 Because the total number of all 3 fruits sold is 50

.5b + .75o + .75a = $33.50 The number of each fruit, multiplied by the price of each fruit, and added together is $33.50

They sold twice as many bananas than oranges.

If o is oranges, then 2o = b because there are twice as many bananas so:

b + o + a = 50

2o + o + a = 50

3o + a = 50

Now we can solve.

3o + a = 50

a = 50 - 3o

.5b + .75o + .75a = $33.50

.5(2o) + .75o + .75a = $33.50

o + .75o + .75a = $33.50

1.75o + .75a = $33.50

Two equations and 2 unknowns.

a = 50 - 3o

1.75o + .75a = $33.50 Plug in a to solve for o.

1.75o + .75(50 - 3o) = $33.50

1.75o + .75*50 - .75*3o = $33.50

1.75o + 37.5 - 2.25o = $33.50 Combine like terms

1.75o - 2.25o +37.5 = $33.50

-.5o + 37.5 = 33.5 Add .5o to each side so it cancels on the left.

37.5 = 33.5 + .5o Subtract 33.5 from each side

37.5 -33.5 = .5o

4 = .5o Divide each side by .5

4/.5 = o

8 = o

Now plug into a = 50 - 3o

a = 50 - 3(8)

a = 50 - 24

a = 26

So even though we know they sold 26 apples, let's finish solving to check our work.

b + o + a = 50

b + 8 + 26 = 50

b + 34 = 50

b = 50 - 34

b = 16

b = 2o

b = 2 (8)

b = 16 Which works! Now the last step of checking our work:

.5b + .75o + .75a = $33.50

.5(16) + .75(8) + .75(26) = $33.50

8 + 6 + 19.5 = $33.50

14 + 19.5 = $33.50

33.5 = $33.50 Yes! It works too!

bananas = 16

oranges = 8

apples = 26

3 0

2 years ago

The area of a rectangle is 20 square meters. How long is the length, if the width is 4 meters?

Brums [2.3K]

To find, the length, divide the area by the width:

Length = 20 / 4 = 5 meters.

4 0

2 years ago

Which polynomial is prime? Ox+3x²-x²-3 Ox4-3x²-x² + 3 O 3x²+x-6x-2 O 3x²+x-6x + 3

GarryVolchara [31]

Answer:

The polynomial 3x² + x - 6x + 3 is a prime polynomial

How to determine the prime polynomial?

For a polynomial to be prime, it means that the polynomial cannot be divided into factors

From the list of options, the polynomial (D) is prime, and the proof is as follows:

We have:

3x² + x - 6x + 3

From the graph of the polynomial (see attachment), we can see that the function does not cross the x-axis.

Hence, the polynomial 3x² + x - 6x + 3 is a prime polynomial

Read more about prime polynomial at:

brainly.com/question/2944912

#SPJ5

8 0

1 year ago

A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 90 m long and 66 m wide.

almond37 [142]

I hope this helps you

6 0

2 years ago

when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.

sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3>Solution:</h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = $a^2$

6 is subtracted from the square of a number = $a^2 - 6$

5 times the number = $5 \times a$

So we can frame a equation as:

6 is subtracted from the square of a number = 5 times the number

$a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0$

Let us solve the above quadratic equation

For a quadratic equation $ax^2 + bx + c = 0$ where $a \neq 0$

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here in this problem,

$a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6$

Substituting the values in above quadratic formula, we get

$\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}$

We have two solutions for "a"

$\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}$

We have asked negative solution. So a = -1

Thus the negative solution is -1

6 0

2 years ago

Please answer both thank you​

Please answer both thank you