Construct a trapezium ABCD such that AD is parallel to BC, AB = 4.8 cm, BC = 6.8 cm, CD = 5.4 cm and ∠ABC = 60°. Measure and wri
te down the length of AC.
1 answer:
Answer:
AC = 6.05 cm
Step-by-step explanation:
We can draw two different trapeziums with the information given.
The possible drawings of the trapezium ABCD are in the image attached.
In both trapeziums, the length of AC is the same, and we can calculate this length using the law of cosines in the triangle ABC:
AC^2 = AB^2 + BC^2 - 2 * AB * BC * cos(B)
AC^2 = 4.8^2 + 6.8^2 - 2 * 4.8 * 6.8 * cos(60)
AC^2 = 23.04 + 46.24 - 65.28 * 0.5
AC^2 = 36.64
AC = 6.05 cm
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a. the cost of a call for six minutes is 0.70.
b.the cost of a 14-minute call is 2.62.
c.the cost of a 9 ½2-minute call is 1.66.
<h3>How to find the cost of each call ?</h3>given that
rate schedule for an m-minute call from any of its pay phones 0.70.
c(m) = 0.70 when m<=6
c(m) = 0.70+ 0.24(m-6) when m>6 & m is an integer
c(m) = 0.70+0.24((m-6)+1) when m>6 & m is not an integer.
a. to find the cost of a call for six minutes.
already given that c(m) =0.70 when m=6.
Therefore, the cost of a call for six minutes is 0.70.
b. to find the cost of a 14-minute call.
according to given information
Therefore,the cost of a 14-minute call is 2.62.
c.to find the cost of a 9 ½2-minute call
according to given information
Therefore,the cost of a 9 ½2-minute call is 1.66.
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