First, you need to move 2 to the other side. You accomplish this by adding 2 to 1. You have y>3. Since your variable is smaller than 3, draw an open circle on the 3 mark and a squiggly line left of 3.
Answer: seven and twenty-five hundredths
Step-by-step explanation:
just need to know how to say it
X+y+5=0
y=-x-5
If a solution exists y=y so we can say
x^2-9x+10=-x-5 add x+5 to both sides
x^2-8x+15=0 now factor
x^2-3x-5x+15=0
x(x-3)-5(x-3)
(x-5)(x-3) so x=3 and 5, using y=-x-5
y(3)=-8 and y(5)=-10
So the two solutions are:
(3,-8) and (5,-10)
Since its x + 3 we use -3
-3| 2 1 -8 21 (these are the # without the x)
___________________
-6 15 -21
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2 -5 7 0
Drag the 2 down, multiple it by -3 to get -6
1+(-6) = -5. -5 * -3 =15 . 15+(-8) = 7
7*-3 = -21. -21 +21 = 0
Since last # is 0 we have a factor.
factor is 2x^2 -5x -7 (we start with a power 1 less the original.)
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Answer:
-3
Step-by-step explanation:
You cant count the spaces up (9) and over (-3) between the two points and do up/over so it would be 9/-3 and simplified that is -3/1 or 3
