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lys-0071 [83]
3 years ago
7

Solve for X

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
3 0

Answer:

x = 1035 = MXXXV

Step-by-step explanation:

<u>Roman Numbers </u>

It's an ancient number system developed in Rome where numbers are represented by the letters {I,V,X,L,C,D,M}. The value of each are, respectively {1,5,10,50,100,500,1000}. If some letter is repeated, then it's value must be multiplied by the number of times the letter is present. For example, XXVII has two X's and two I's, so the conversion is 10+10+5+1+1=27.

If a less-valued letter appears before a greater one, it subtracts. For example CDI=-100+500+1=401

Our numbers are

MMMMMMMMCDXV=8*1000-100+500+10+5=8415

MDCCCLXIII = 1000+500+300+50+10+3=1863

DLXI = 500+50+10+1=561

XXVII = 20+5+2=27

We now operate in our numerical system

\displaystyle x = \frac{MMMMMMMMCDXV * MDCCCLXIII}{DLXI * XXVII}

\displaystyle x = \frac{8415 * 1863}{561 * 27}

\displaystyle x = \frac{15677145}{15147}

\displaystyle x = 1035

Converting back to roman

\boxed{\displaystyle x = MXXXV}

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Answer:

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Step-by-step explanation:

Since sqrt(a) and sqrt(b) are in simplest radical form, that means a and b have no perfect square factors. When sqrt(a) and sqrt(b) are multiplied giving c * sqrt(d), the fact that c came out of the root means that there was c^2 inside the product sqrt(ab). This means that a and b have at least one common factor.

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Example:

Let a = 6 and let b = 10.

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Now we multiply the radicals.

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We have c = 2 and d = 15.

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Step-by-step explanation:

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  2. When 4 is added to 3x , algebrically it is written as "3x + 4".
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