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lys-0071 [83]
3 years ago
7

Solve for X

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
3 0

Answer:

x = 1035 = MXXXV

Step-by-step explanation:

<u>Roman Numbers </u>

It's an ancient number system developed in Rome where numbers are represented by the letters {I,V,X,L,C,D,M}. The value of each are, respectively {1,5,10,50,100,500,1000}. If some letter is repeated, then it's value must be multiplied by the number of times the letter is present. For example, XXVII has two X's and two I's, so the conversion is 10+10+5+1+1=27.

If a less-valued letter appears before a greater one, it subtracts. For example CDI=-100+500+1=401

Our numbers are

MMMMMMMMCDXV=8*1000-100+500+10+5=8415

MDCCCLXIII = 1000+500+300+50+10+3=1863

DLXI = 500+50+10+1=561

XXVII = 20+5+2=27

We now operate in our numerical system

\displaystyle x = \frac{MMMMMMMMCDXV * MDCCCLXIII}{DLXI * XXVII}

\displaystyle x = \frac{8415 * 1863}{561 * 27}

\displaystyle x = \frac{15677145}{15147}

\displaystyle x = 1035

Converting back to roman

\boxed{\displaystyle x = MXXXV}

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