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3 years ago

How do u find the mean

Mathematics

2 answers:

dusya [7]3 years ago

7 0

You add all the numbers & divide it by how many numbers 8 +9+9+9+10+10

alexgriva [62]3 years ago

7 0

Answer,

The mean is the average of the numbers. It's quite simple to find the mean. All you do is, add all the numbers togter & divide by how many numbers there are. In simpler words, it is the sum divided by the count.

I'm not sure if you are trying to find the mean for only one row or all the rows together but, I will show you how to do it for all the numbers.

The mean of the numbers is, 12.47619047619.

Explanation, 8+9+9+9+10+10+11+11+12+12+12+12+13+13+13+14+14+15+15+16+24= 262.

Then we divide 262 by how many numbers there are, 21. Then we get 12.47619047619.

Hope this helps :-)

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A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

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$p_A$ represent the real population proportion female for Biology

$\hat p_A =\frac{84199}{144796}=0.582$ represent the estimated proportion female for biology

$n_A=144796$ is the sample size for A

$p_B$ represent the real population proportion female for calculus AB

$\hat p_B =\frac{102598}{211693}=0.485$ represent the estimated proportion female for Calculus AB

$n_B=211693$ is the sample size required for B

$z$ represent the critical value for the margin of error

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$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.