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ICE Princess25 [194]
2 years ago
10

Help with 38 and 39 please!! 15 pts!!!

Mathematics
2 answers:
Temka [501]2 years ago
6 0

Answer:

38. -2.2

39. -1

Step-by-step explanation:

38.

First let's count how far C is from F.

5 - (-4)=5 + 4 = 9

There are 9 spaces between C and F.

Let's find 9/5, which is 1.8

Because we're finding the distance from C to F, we add 1.8 to the value C.

-4 + 1.8 = -2.2

The point X in CF that is 1/5 of the distance from C to F is -2.2

Note: It's your judgement on whether or not your professor would want this in decimal form or rounded to -2. I'd keep it as -2.2 if you're not sure, because that is the correct answer.

39.

Now let's do the same thing with BD.

How far is B from D? 1 - (-5) = 1 + 5 = 6

What's (6*2)/3? 12/3 = 4

What's B + 4? -5 + 4 = -1

The point X on BD that is 2/3 of the distance from B to D.  is -1

fgiga [73]2 years ago
3 0

Answer: X=-2 1/5, X=-1

Step-by-step explanation:

The distance from CF is 9 units, 1/5 that = 1 4/5, add that to -4 is -2 1/5.

The distance from BD is 6 units, 2/3 that =4, add that to -5 is -1.

Hope this helps!

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Sunspots have been observed for many centuries. Records of sunspots from ancient Persian and Chinese astronomers go back thousan
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Answer:

(a) Null Hypothesis, H_0 : \mu \leq 41  

    Alternate Hypothesis, H_A : \mu > 41

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Step-by-step explanation:

We are given that in a random sample of 40 such periods from Spanish colonial times, the sample mean is x¯ = 47.0. Previous studies of sunspot activity during this period indicate that σ = 35.

It is thought that for thousands of years, the mean number of sunspots per 4-week period was about µ = 41.

Let \mu = <u><em>mean sunspot activity during the Spanish colonial period.</em></u>

(a) Null Hypothesis, H_0 : \mu \leq 41     {means that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41}

Alternate Hypothesis, H_A : \mu > 41     {means that the mean sunspot activity during the Spanish colonial period was higher than 41}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean = 47

            σ = population standard deviation = 35

            n = sample of periods from Spanish colonial times = 40

So, <em><u>the test statistics</u></em>  =  \frac{47-41}{\frac{35}{\sqrt{40} } }

                                      =  1.08

(b) The value of z test statistics is 1.08.

(c) <u>Now, the P-value of the test statistics is given by;</u>

                P-value = P(Z > 1.08) = 1 - P(Z < 1.08)

                              = 1 - 0.8599 = <u>0.1401</u>

Since, the P-value of the test statistics is higher than the level of significance as 0.1401 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

8 0
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