The equation is 
.
1/2 is equivalent to 4/8, and 2 1/8 is equal to 17/8. (two full sets of 8 + 1 = 8 + 8 + 1, or 17)
The new equation is 
. Subtract the numerators.
17 - 4 = 13 or 13/8
The improper fraction 
simplifies to 
.
<h2>Answer:</h2>
Hope this helps :)
D is your answer. The last dot
Answer: You have six numbers on your ticket. In drawing the first number from the collection of 45, one of those six numbers must be drawn in order for you to still have a chance of winning the big prize. So following the draw, the probability is only 6/45 (or 1/9) that you’re still in the game.
You can now see that on each successive draw the probability steadily drops- to 5/44, 4/43, 3/42, 2/41, and for the last number 1/40. As other answers have stated, there are 8,145,060 possible draws of six numbers and only one makes you a winner.
If you bought ten tickets for every drawing, the odds reach a 50% chance of having won at about 520,550 drawings. Assuming two drawings per week, the chance of winning reaches 50% in about 5,200 years.
Of course, SOMEONE will win and if you don’t play, your chance of winning is zero. It’s kind of fun to occasionally buy lottery tickets just for the dream of winning but don’t spend a lot of money on them.
5.9K viewsView upvotes · Answer requested by Arthur C. Thorpe
7
Related Questions (More Answers Below)
Step-by-step explanation:
me need slope and y intercept to get it in y=mx+b form (slope intercept)
Slope is the
difference in y / differences in x
differences in y = 6.5 -3 = 3.5
difference in x = 2 - 1 = 1
so slope is 3.5/1 or just 3.5
(now you can see the answer is c but lets check it by getting the y intercept too)
y intercept
this is when x is 0
the lowest x we see is 1 so if I go bacl to 0 in x the y must for back 3.5
3-3.5 is -0.5
so equation is y=3.5x -0.5 so the closest is c
Repeated measures study is when participants of the first treatment are still the participants of the second treatment either to see the effects of the variable. Thank you for your question. Please don't hesitate to ask in Brainly your queries.
