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Ierofanga [76]
3 years ago
11

Graphing Polynomial Functions

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
3 0

Answer:

table and graph attached

Step-by-step explanation:

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The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas
saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by s(t) = -t^3+3t^2+7t +4, where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

s(t) = -t^3+3t^2+7t +4

Derivate w.r.t. time,

v(t)=s'(t) = -3t^2+6t+7

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

x=-\frac{b}{2a}

Where, a=-3, b=6 and c=7

t=-\frac{6}{2(-3)}

t=-\frac{6}{-6}

t=1

As 1 lie between interval [0,4]

Substitute t=1 in the function,

v(t)= -3(1)^2+6(1)+7

v(t)= -3+6+7

v(1)=10

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0
3 years ago
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dmitriy555 [2]
The answer is going to be <span>327421537466</span>
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3 years ago
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If you multiply me by 2, then divide the answer by 2, then divide again by 2, you get a quotient of 5. What number am I?
Anuta_ua [19.1K]
The number is 10
10*2=20
20/2=10
10/2=5
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3 years ago
Easy but i'm confused yikes. (picture attached)
kirill115 [55]

Answer:

The second answer

Step-by-step explanation:

P'Q'R' is simply rotating PQR 90 degrees, it does not change the angle that it makes

8 0
3 years ago
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Is 2/3 greater than 9/10??????? ANSWER NOW
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No it is not , it is less than 9/10.
7 0
3 years ago
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