Ask question

Ask question

All categories

Dennis_Churaev [7]

2 years ago

13

You shopped online and found you mp3 player for $9.75 less than the store price p. The online price was $64. Write and solve an

equation to find the store price

1 answer:

katrin [286]2 years ago

4 0

Answer:

64 = p - 9.75
p = 73.75

Step-by-step explanation:

A value that is 9.75 less than p can be represented by the expression ...

p - 9.75

We are told that value is equal to 64, so the equation is ...

64 = p - 9.75

__

This equation is solved by adding 9.75 to both sides.

64 +9.75 = p -9.75 +9.75

73.75 = p

The store price is $73.75.

You might be interested in

Name the types of angles shown.

PIT_PIT [208]

< ABC is a straight angle
no right angles
no complimentary angles
< ABD and < DBC are supplementary angles

7 0

2 years ago

Read 2 more answers

Please solve 5 f <br> (Trigonometric Equations)<br> #salute u if u solved it

Zanzabum

Answer:

$\beta=45\degree\:\:or\:\:\beta=135\degree$

Step-by-step explanation:

We want to solve $\tan \beta \sec \beta=\sqrt{2}$ , where $0\le \beta \le360\degree$ .

We rewrite in terms of sine and cosine.

$\frac{\sin \beta}{\cos \beta} \cdot \frac{1}{\cos \beta} =\sqrt{2}$

$\frac{\sin \beta}{\cos^2\beta}=\sqrt{2}$

Use the Pythagorean identity: $\cos^2\beta=1-\sin^2\beta$ .

$\frac{\sin \beta}{1-\sin^2\beta}=\sqrt{2}$

$\implies \sin \beta=\sqrt{2}(1-\sin^2\beta)$

$\implies \sin \beta=\sqrt{2}-\sqrt{2}\sin^2\beta$

$\implies \sqrt{2}\sin^2\beta+\sin \beta- \sqrt{2}=0$

This is a quadratic equation in $\sin \beta$ .

By the quadratic formula, we have:

$\sin \beta=\frac{-1\pm \sqrt{1^2-4(\sqrt{2})(-\sqrt{2} ) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{1^2+4(2) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{9} }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm3}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{2}{2\cdot \sqrt{2} }$ or $\sin \beta=\frac{-4}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{1}{\sqrt{2} }$ or $\sin \beta=-\frac{2}{\sqrt{2} }$

$\sin \beta=\frac{\sqrt{2}}{2}$ or $\sin \beta=-\sqrt{2}$

When $\sin \beta=\frac{\sqrt{2}}{2}$ , $\beta=\sin ^{-1}(\frac{\sqrt{2} }{2} )$

$\implies \beta=45\degree\:\:or\:\:\beta=135\degree$ on the interval $0\le \beta \le360\degree$ .

When $\sin \beta=-\sqrt{2}$ , $\beta$ is not defined because $-1\le \sin \beta \le1$

4 0

2 years ago

Which graphs display a directly proportional relationship? Check all that apply.

Vedmedyk [2.9K]

The one that goes from corner to corner......i think if i get it wrong sorry

8 0

3 years ago

Read 2 more answers

Hello please help me <br> Idk if the answer is 16 or 19 <br><br> 4 - 16 ÷ 4 + 4²

ivann1987 [24]

The answer is 16 because you have to do the exponents, than the division, then the subtraction, and lastly, the addition.

4 0

2 years ago

Davids scores on the first three of four 100-point math tests were 86, 92, and 89. What score does he need on his fourth math te

Musya8 [376]

The answer is (B) x > 93

3 0

3 years ago