F(1) = 160 is given to us. We'll use it to find f(2)
f(n+1) = -2*f(n)
f(1+1) = -2*f(1) ... replace every n with 1
f(1+1) = -2*160 ... replace f(1) with 160
f(2) = -320
Now use f(2) to find f(3)
f(n+1) = -2*f(n)
f(2+1) = -2*f(2) ... replace every n with 2
f(3) = -2*(-320) ... replace f(2) with -320
f(3) = 640
Finally, use f(3) to find f(4)
f(n+1) = -2*f(n)
f(3+1) = -2*f(3) ... replace every n with 3
f(4) = -2*640 ... replace f(3) with 640
f(4) = -1280
Final Answer: -1280
Answer:
(12 2/3)/( 2 1/3)= 38/7 or 5 3/7 or 5.43 decimal
Step-by-step explanation:
Simplify the following:
(12 + 2/3)/(2 + 1/3)
Put 2 + 1/3 over the common denominator 3. 2 + 1/3 = (3×2)/3 + 1/3:
(12 + 2/3)/((3×2)/3 + 1/3)
3×2 = 6:
(12 + 2/3)/(6/3 + 1/3)
6/3 + 1/3 = (6 + 1)/3:
(12 + 2/3)/((6 + 1)/3)
6 + 1 = 7:
(12 + 2/3)/(7/3)
Put 12 + 2/3 over the common denominator 3. 12 + 2/3 = (3×12)/3 + 2/3:
((3×12)/3 + 2/3)/(7/3)
3×12 = 36:
(36/3 + 2/3)/(7/3)
36/3 + 2/3 = (36 + 2)/3:
((36 + 2)/3)/(7/3)
36 + 2 = 38:
(38/3)/(7/3)
Multiply the numerator by the reciprocal of the denominator, (38/3)/(7/3) = 38/3×3/7:
(38×3)/(3×7)
(38×3)/(3×7) = 3/3×38/7 = 38/7:
Answer: 38/7
Lets write down the information that we know.
Jessie has 7 stacks of 6 dimes, so Jessie has a total of 6*7 dimes
Dimes=7*6=42dimes
Jessie has 42 dimes, but then she found another one so lets add one more dime.
42+1=43 dimes
Jessie has 8 stacks of 5 nickels, so Jessie has 8*5 nickels
Nickels=8*5=40nickels
Jessie has 40 nickels, but then she found another one so lets add 1 to the total number of nickels.
40+1=41nickels
Now we can answer the question.
How many dimes and nickels does jessie have in all?
nickels+dimes=
41+43=84 coins
Jessie has 84 coins in total
what do you meanAnswer:
Step-by-step explanation:
We define the variables:
p: cost of bushel of peaches
w: cost of watermelon
We wrote the system of equations:
12p + 5w = 150
15p + 8w = 198
We can represent the system in matrix form as
Ax = b
Where,
A = [12 5; 15 8]
b = [150; 198]
x = [p; w]
