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nadezda [96]
3 years ago
7

I will give u brainliest

Mathematics
1 answer:
spayn [35]3 years ago
4 0

Answer:

9

Step-by-step explanation:

sqrt(85) is about 9.2, and the question asks to round to the nearest integer, making it 9. 9.2^2 is almost 85, which is how you can check your answer.

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Find AB. Round to the nearest tenth if necessary.<br>​
shusha [124]

Answer:

I think the right answer would be 7

Step-by-step explanation:

We got-ta use the equation: CA * BA = DA²

CA = 15 + BA

DA² = 8² = 64

=> (15 + BA) BA = 64

Subtract 15 from each side:

BA(BA) = 49

BA² = 49

Now take the square root of each side

BA = 7

Hope this helps!

3 0
3 years ago
Pregunt<br> A={x/x es un dia de la semana} expresado por extensión se escribe como<br> A= {lunes)
cestrela7 [59]

Answer:

sorry, dont speak spanish

Step-by-step explanation:

7 0
3 years ago
If i got 576 pets and then i leave 111 pets and then add another 890 how much do i have in total​
algol [13]

Answer:

1355 pets

Step-by-step explanation:

576 pets - 111 pets = 465 pets

465 pets + 890 pets = 1355 pets

5 0
3 years ago
Read 2 more answers
12. Find u · v for u = 3i + 4j and v = i - 2j
Ugo [173]
ANSWER: -3-2ji-8j^2

EXPLAINATION:

I dont know why that isn’t one of the answers but that’s what I got. You could try D.

MARK ME BRAINLIEST PLEASE
7 0
3 years ago
A sales and marketing management magazine conducted a survey on salespeople cheating on their
Alenkinab [10]

Answer:

The 95% confidence interval estimate of the population proportion of managers who have caught salespeople cheating on an expense report is (0.5116, 0.6484).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

In the survey on 200 managers, 58% of the managers have caught salespeople cheating on an expense report.

This means that n = 200, \pi = 0.58

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.58 - 1.96\sqrt{\frac{0.58*0.42}{200}} = 0.5116

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.58 + 1.96\sqrt{\frac{0.58*0.42}{200}} = 0.6484

The 95% confidence interval estimate of the population proportion of managers who have caught salespeople cheating on an expense report is (0.5116, 0.6484).

7 0
3 years ago
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