Average=(total number)/(number of items)
given that the final exam counts as two test, let the final exam be x. The weight of the final exams on the average is 2, thus the final exam can be written as 2x because any score Shureka gets will be doubled before the averaging.
Hence our inequality will be as follows:
(67+68+76+63+2x)/6≥71
(274+2x)/6≥71
solving the above we get:
274+2x≥71×6
274+2x≥426
2x≥426-274
2x≥152
x≥76
b] The above answer is x≥76, the mean of this is that if Shureka is aiming at getting an average of 71 or above, then she should be able to get a minimum score of 76 or above. Anything less than 76 will drop her average lower than 71.
<u>Answer:</u>
80
<u>Step-by-step explanation:</u>
(27-15):15*100 =
(27:15-1)*100 =
180-100 = 80
I hope this helped!
Sincerely,
Rekifromsk8theinfinity
:D
Answer:
y = 4/3
Step-by-step explanation:
Answer:
(-3,-6)
Step-by-step explanation:
The first coordinate is the x coordinate
X is 3 units to the left so it is -3
The next coordinate is the y coordinate
Y is 6 units down so it is -6
(-3,-6)
The number of large boxes is 4 and the number of small boxes is 14.
<u><em>Explanation</em></u>
Suppose, the number of large boxes is 
and the number of small boxes is 
As, the total number of boxes is 18, so the first equation is....
The large boxes hold 35 books, and the small ones hold 20 books and the total number of books is 420. So the second equation will be .....
Now solving equation (1) for itself , we will get....
We will plug this into equation (2). So.....
Now plugging this 
into the equation .......
Thus, the number of large boxes is 4 and the number of small boxes is 14.
