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12345 [234]
3 years ago
15

8................................

Mathematics
1 answer:
mariarad [96]3 years ago
8 0

Answer is :

3{a}^{4}  {b}^{3}

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*The sum of two numbers is 400. If the first number is decreased by 20% and the second number is decreased by 15%, then the sum
Dahasolnce [82]

Answer:

The two numbers are .8*160=128 and .85*240=204

Step-by-step explanation:

First sentence:                 x+y=400

Second sentence           .8x+.85y=400-68

Solve y in the first sentence:  y=400-x

Plug first into second:     .8x+.85(400-x)=332

Distribute:                        .8x+.85(400)-.85x=332

Combine like terms:        -.05x+.85(400)=332

Simplify(multiply):              -.05x+      340=332

Subtract 340 on both sides:    -.05x       =332-340

Simplify(subtract):                     -.05x        =-8

Divide both sides by -.05:              x        =-8/-.05

Simplify (division):                           x        = 160

So y=400-x=400-160=240

8 0
3 years ago
Read 2 more answers
a music store is advertising a 25% off sale on all new releases find the discount and the sale price of a newly released CD that
ludmilkaskok [199]
Discount=$3.13
sale=$9.38
4 0
3 years ago
Combine like terms to write the expression in simplest form.<br> 42? + 5y? 2² - 3y²<br> 3y” — Бу
rosijanka [135]

Answer:Missing: 3y² ‎Бу

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
PLEASE HELP 50 POINTS 100 students who are in 10th or 11th grade were asked if they participated in at least one extracurricular
Marina86 [1]

There are 2 variables in this problem. One variable is the class number and other variable is the participation in extracurricular activities. Each variable has further two categories. There are two classes: Class 10 and 11. And students either participate or do not participate in extracurricular activities, which makes 2 categories. 

The best approach to solve this question is to build a table and start entering the given information in it. When the given data has been entered fill the rest on basis of the data you have.

18 students from grade 11 participate in at least one Extracurricular activities. This means the rest students i.e. 22 students from grade 11 do not participate in Extracurricular activities. 

32 students from grade 10 participate in at least one Extracurricular activities. This means total students who participate in at least one Extracurricular activities are 18 + 32 = 50 students.

The rest 50 students do not participate in at least one Extracurricular activities. From these 22 are from class 11. So the rest i.e. 28 are from class 10.

5 0
3 years ago
If cot theta= 4/3, find csc theta
Marrrta [24]

Answer: Option d.

Step-by-step explanation:

The trigonometric identity needed is:

csc^2\theta=cot^2\theta+1

Knowing that cot\theta=\frac{4}{3}:

Substitute it into csc^2\theta=cot^2\theta+1:

csc^2\theta=(\frac{4}{3})^2+1

Simplify the expression:

csc^2\theta=(\frac{4}{3})^2+1\\\\csc^2\theta=\frac{16}{9}+1\\\\csc^2\theta=\frac{25}{9}

Solve for csc\theta. Apply square root at both sides of the expression:

\sqrt{csc^2\theta}=\±\sqrt{\frac{25}{9}}

csc\theta=\frac{5}{3}

8 0
2 years ago
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