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kotykmax [81]
2 years ago
6

Which algebraic expression has a term with a coefficient of 3?

Mathematics
1 answer:
Musya8 [376]2 years ago
5 0
A. Is the answer because a coefficient is the number that is attached to a variable or in front of it. There cannot be a parenthesis in between them like in letter D. So your answer is letter A because the 3 in 3y+1 is a coefficient. Hope this helps!
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What is the meaning of the point (25, 20)?
Reil [10]

Answer:

(25, 20 ) represents that the dimension of the coral is 25 feet long and 20 feet wide.

Step-by-step explanation:

The general representation P(x,y) represents the Cartesian Representation of a point in a 2 Dimension.

Here, x represents the distance of the point   P from y axis to the x axis.

and y  represents the distance of the point   P from x axis to the y axis.

(x, y) together gives the  2 dimensional representation of the point P.

Now here, the given coordinates are (25, 20)

So, here x = 25 and y = 20

So, (25, 20 ) represents that the dimension of the coral  is 25 feet long and 20 feet wide.

Hence, option 3 is the most appropriate.

6 0
2 years ago
Are these a rational function?
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HELp ME 100 points if you awncer and branlyest
boyakko [2]

Answer:

its the middle 3

Step-by-step explanation:

B C and D

5 0
2 years ago
Read 2 more answers
Five friends buy tickets to a carnival. They each also spend $4 on a funnel cake. They spent a total of $60. How much does one t
Butoxors [25]

Answer:

$8 for each tickets

Step-by-step explanation: 60/5 equals 12

Each friends have $12

12-4=8

Each ticked cost 8 dollars.

4 0
2 years ago
At Prairieview Middle School, 100 students participate in at least one of three after-school clubs: soccer club, art club, and g
Tresset [83]

Answer:

17

Step-by-step explanation:

Number of students in soccer club, n(S) = 50

Number of students in Art club, n(A) = 53

Number of students in Gaming club, n(G)

n(S \cup A\cup G) = 100

n(S \cap A\cap G) = 9

n(S \cap A) = 20

n(A \cap G) = 35

n(G \cap S) = 29

Formula:

n ( A ∪ B ∪ C ) =  n(A) + n(B) + n(C) – n ( A ∩ B ) – n(B ∩ C) – n (A ∩ C) + n( A ∩ B ∩ C )

Putting the values:

100 = 50 + 53 + n(G) - 20 - 35 - 29 + 9

100 = 112 + n(G) - 84

n(G) = 72

Number of students in gaming club only = n(G) - n(G \cap S) - n(A \cap G) + n(S \cap A\cap G)

= 72 - 35 - 29 + 9

= <em>17</em>

6 0
3 years ago
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