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Maru [420]
3 years ago
6

Write the equation of a line that passes through the point (-2,7) and perpendicular to a line that passes through the points (-6

,1) and (0,4)
Mathematics
1 answer:
Alexandra [31]3 years ago
8 0

Answer:

Step-by-step explanation:

(x₁, y₁)= (-6,1)  and (x₂,y₂) = (0,4)

Slope = \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

          = \dfrac{4-1}{0-[-6]}\\\\=\dfrac{3}{0+6}\\\\=\dfrac{3}{6}\\\\=\dfrac{1}{2}

Slope of line perpendicular to it = -1/m  

                                                     = \dfrac{-1}{\dfrac{1}{2}}\\\\=-1*\dfrac{2}{1}=-2

Equation : y =mx +b

y = -2x + b

Plugin x = -2 and y =7 in the above equation

7 = -2*(-2) + b

7 = 4 + b

7-4=b

3 = b

Equation: y =-2x + 3

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