Question

Write the equation of a line that passes through the point (-2,7) and perpendicular to a line that passes through the points (-6,1) and (0,4)

Answer 1

Answer:

Step-by-step explanation:

(x₁, y₁)= (-6,1)  and (x₂,y₂) = (0,4)

Slope = $\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

          $= \dfrac{4-1}{0-[-6]}\\\\=\dfrac{3}{0+6}\\\\=\dfrac{3}{6}\\\\=\dfrac{1}{2}$

Slope of line perpendicular to it = -1/m  

                                                     $= \dfrac{-1}{\dfrac{1}{2}}\\\\=-1*\dfrac{2}{1}=-2$

Equation : y =mx +b

y = -2x + b

Plugin x = -2 and y =7 in the above equation

7 = -2*(-2) + b

7 = 4 + b

7-4=b

3 = b

Equation: y =-2x + 3