Answer:
ok
Step-by-step explanation:
pls give brainlest almost lvled up
5.
x = -1
y = 3
Step-by-step explanation:
you'll want to cancel the y numbers
5.
-2x-9y=-25
-4x-9y=-23
multiply the bottom with -1 so that you have
positive or +9y
-2x-9y= -25
-1 times (-4x-9y= -23)
-2x-9y= -25
+4x+9y= +23
this equals
2x = -2
x = -1
put -1 where the x is in -2x-9y= -25 to get y
-2(-1) -9y = -25 =
+2 -9y = -25
-9y = -27
y = 3
6.
8x+ y= -16
-3x+ y= -5
multiply 8x+ y= -16 with +3 AND
multiply -3x+ y= -5 with -8
so you can cancel out the x's
+3 (8x+ y= -16)
-8 times (-3x+ y= -5)
8x+ y= -16
+3x -y= +5
equals
24x+ 3y= -48
-24x +8y= -40
11y = -88
y = -8
Answer:
y·y"-(y')= Yy" - y'
2-(y')=2-y'
3=0==0
step-by-step explanation:
use the given functions to set up and simplify 2-(y')
The points you found are the vertices of the feasible region. I agree with the first three points you got. However, the last point should be (25/11, 35/11). This point is at the of the intersection of the two lines 8x-y = 15 and 3x+y = 10
So the four vertex points are:
(1,9)
(1,7)
(3,9)
(25/11, 35/11)
Plug each of those points, one at a time, into the objective function z = 7x+2y. The goal is to find the largest value of z
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Plug in (x,y) = (1,9)
z = 7x+2y
z = 7(1)+2(9)
z = 7+18
z = 25
We'll use this value later.
So let's call it A. Let A = 25
Plug in (x,y) = (1,7)
z = 7x+2y
z = 7(1)+2(7)
z = 7+14
z = 21
Call this value B = 21 so we can refer to it later
Plug in (x,y) = (3,9)
z = 7x+2y
z = 7(3)+2(9)
z = 21+18
z = 39
Let C = 39 so we can use it later
Finally, plug in (x,y) = (25/11, 35/11)
z = 7x+2y
z = 7(25/11)+2(35/11)
z = 175/11 + 70/11
z = 245/11
z = 22.2727 which is approximate
Let D = 22.2727
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In summary, we found
A = 25
B = 21
C = 39
D = 22.2727
The value C = 39 is the largest of the four results. This value corresponded to (x,y) = (3,9)
Therefore the max value of z is z = 39 and it happens when (x,y) = (3,9)
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Final Answer: 39