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Paha777 [63]
3 years ago
15

How do I find the the perimeter of a rectangle in a coordinate plane

Mathematics
1 answer:
pashok25 [27]3 years ago
3 0

From the way you worded the question, it sounds like you have
the (x, y) coordinates of each corner of the rectangle.

The perimeter of any shape is the distance all the way around it,
or the sum of the lengths of all the sides.

So you have to take the coordinates of the four corners of the
rectangle, and find the length of each side ... that's the distance
between each pair of corner-points.  Then addum up to get the
perimeter.

I know finding the distance between two points is a pain, so I'll
tell you a way to make it a bit simpler:  You don't actually need to
do it 4 times.  You can get away with doing it only 2 times, and
you'll have enough information to find the perimeter.

Take the coordinates at the ends of any side of the rectangle.
Find the distance between them.  The side opposite that one
has the same length.

Then take the coordinates of either side that hooks onto the
side you just did.  One end of it will have the same coordinates
that you just worked with.  Find the distance between the two ends.
You know that this distance is the other dimension of the rectangle,
and you also know that the side opposite it has the same length.

So now, you found the distance between two pairs of points,
and you know both dimensions of the rectangle, and you know
the length of all four sides.

Now you can wrap it up !

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Right triangles 1,2 and 3 are given to its all their angle measures and approximate side lengths
Ede4ka [16]

Answer:

5.4 units

Step-by-step explanation:

From the figure ,it's clear that   sin(50) = PQ/7

Then

PQ = 7×sin(50) = 5.362311101833

Therefore the approximate length of PQ I saw 5.4

6 0
2 years ago
What is the initial value in the equation f(x) = 350(1 - 0.12)^x? *
kvasek [131]

Given:

The function is:

f(x)=350(1-0.12)^x

To find:

The initial value of the function.

Solution:

We have,

f(x)=350(1-0.12)^x

The value of the function at x=0 is called the initial value of the function.

For x=0, we get

f(0)=350(1-0.12)^0

f(0)=350(0.88)^0

Clearly 0.88 is a non zero number and zero to the power of a non zero number is always 1.

f(0)=350(1)

f(0)=350

Therefore, the initial value of the function is 350.

5 0
3 years ago
Find the value of the ratio.<br><br> Can someone help please???
USPshnik [31]

Answer:

SOH CAH TOA.....Cosine=adj/hyp...... __cosX=16/30___

SOH CAH TOA,,,,,, Tangent= opp/adj-------- Tan X=36/27

Step-by-step explanation:

3 0
2 years ago
Find the zeros of the following<br> please solve step by step<br> 1. x³+9x²+26x+24=0
Vlad1618 [11]

Answer: -4, -3, -2

Step-by-step explanation:

By inspection, we know x=-2 is a root.

We can thus rewrite the equation as

(x+2)\left(\frac{x^3 + 9x^2 + 26x+24}{x+2} \right)=0\\\\(x+2)(x^2 + 7x+12)=0\\\\(x+2)(x+3)(x+4)=0\\\\x=-4, -3, -2

3 0
1 year ago
A web music store offers two versions of a popular song. The size of the standard version is 2.3 megabytes (MB). The size of the
Effectus [21]

answer

240 standard versions

set up equations

s = number of standard versions

h = number of high quality versions

the total size of all standard versions would be 2.3s since each standard version is 2.3 MB

the total size of all high quality versions would be 4.4h since each standard version is 4.4 MB

add them together to get the total size (2664 MB) of all versions

2664 = 2.3s + 4.4h

since the high quality version was downloaded twice as often as the standard, we can say that

h = 2s

substitute h into equation and solve

2664 = 2.3s + 4.4h

h = 2s

2664 = 2.3s + 4.4(2s)

2664 = 2.3s + 8.8s

2664 = 11.1s

s = 2664/11.1

s = 240

7 0
3 years ago
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