All categories

2 years ago

How do I break up w/ my Best Friend without hurting her????

2 answers:

6 0

I don't see how this is math related but let me ask why do you want to? Best friends don't normally leave when things get tough. I mean I do understand. And I will tell you my opinion if you truly want it as well. Jw.

ANTONII [103]2 years ago

3 0

Thats tough honestly theres no way of NOT hurting her but there's ways to lessen the pain. Speak to her tell her whats on your mind why you want to do it etc. Make it an easy process of you.

You might be interested in

Find the other endpoint of the line segment if:

Vesna [10]

Answer:

( - 15, - 16 )

Step-by-step explanation:

Coordinates of midpoint are ( $\frac{x_{1} +x_{2} }{2}$ , $\frac{y_{1} +y_{2} }{2}$ )

( - 5 + x ) / 2 = - 10 ⇒ x = - 15

( 4 + y ) / 2 = - 6 ⇒ y = - 16

( - 15, - 16 )

5 0

2 years ago

Look at abc. which triangle is congruent abc by the asa criterion

Bad White [126]

There is only 1 triangle

4 0

3 years ago

-2x+5c+6c-3x= Simplify and write the answer.

Irina18 [472]

-2x+5c+6c-3x
-5x+11c=

8 0

3 years ago

Read 2 more answers

Given cosα = −3/5, 180 < α < 270, and sinβ = 12/13, 90 < β < 180

torisob [31]

I got

$- \frac{6 3}{65}$

What we know

cos a=-3/5.

sin b=12/13

Angle A interval are between 180 and 270 or third quadrant

Angle B quadrant is between 90 and 180 or second quadrant.

What we need to find

Cos(b)

Cos(a)

What we are going to apply

Sum and Difference Formulas

Basics Sine and Cosines Identies.

1. Let write out the cos(a-b) formula.

$\cos(a - b) = \cos(a) \cos(b) + \sin(a) \sin(b)$

2. Use the interval it gave us.

According to the given, Angle B must between in second quadrant.

Since sin is opposite/hypotenuse and we are given a sin b=12/13. We. are going to set up an equation using the pythagorean theorem.

${12}^{2} + {y}^{2} = {13}^{2}$

$144 + {y}^{2} = 169$

$25 = {y}^{2}$

$y = 5$

so our adjacent side is 5.

Cosine is adjacent/hypotenuse so our cos b=5/13.

Using the interval it gave us, Angle a must be in the third quadrant. Since cos is adjacent/hypotenuse and we are given cos a=-3/5. We are going to set up an equation using pythagorean theorem,

$( - 3) {}^{2} + {x}^{2} = {5}^{2}$

$9 + {x}^{2} = 25$

${x}^{2} = 16$

$x = 4$

so our opposite side is 4. sin =Opposite/Hypotenuse so our sin a =4/5.Sin is negative in the third quadrant so

sin a =-4/5.

Now use cosine difference formula

$- \frac{3}{5} \times \frac{5}{13} + - \frac {4}{5} \times \frac{12}{13}$

$- \frac{15}{65} + ( - \frac{48}{65} )$

$- \frac{63}{65}$

Hope this helps

6 0

2 years ago

Line perpendicular to the line that goes through (0,0) and (3,2)

KonstantinChe [14]

Since the first line passes thru the origin, you can read off its slope from the coordinates of the other point (3,2): the slope is m = 2/3.

A line perpendicular to the first has slope -3/2, the negative reciprocal of 2/3.

Thus, the perpendicular line is y = (-3/2)x + b. Subbing 0 for y and 0 for x, we get b = 0. Therefore, the equation of this new line is y = (-3/2)x.

7 0

3 years ago