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Ira Lisetskai [31]
1 year ago
13

The mean age of a group of students is 16. John joins the group and the mean age changes to 18. How old is john ?

Mathematics
1 answer:
schepotkina [342]1 year ago
5 0

Answer:

John is 20 years old.

Step-by-step explanation:

Given the second mean is 18, it is equal to the first mean age plus John's unknown age. The sum is also divided by 2 because there are 2 values in the sum (1. John's age and 2. the mean, 16 yrs old).

Set up an equation: \frac{x+16}{2}=18

multiply both sides by 2: x+16=36

simplify: x=20

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Parlings vary directly with mots. If 7.5 mots are worth 37.5 parlings, how many parlings will get you 13 mots?​
snow_lady [41]

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Step-by-step explanation:

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2 years ago
Refer to the following frequency distribution of days absent during a calendar year by employees of a manufacturing company:
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Answer:

(a) 91 employees were absent fewer than six days.

(b) 22 employees were absent more than five days.

(c) 20 employees were absent from 6 up to 12 days.

Step-by-step explanation:

The data for the number of days absent during a calendar year by employees of a manufacturing company is given below.

(a)

The number of employees that were absent for fewer than six days is =

Frequency\  for\  class\ [0\ - \ 3]+Frequency\  for\  class\ [3\ - \ 6]\\=60 +31\\=91

Thus, there were 91 employees who were absent for fewer than six days.

(b)

The number of employees that were absent for more than 5 days is =

Frequency\  for\  class\ [6\ -\ 9]+Frequency\  for\  class\ [9\ -\12]+\\Frequency\ for\  class\ [12\ - \15]\\=14+6+2\\=22

Thus, there were 22 employees who were absent for more than 5 days.

(c)

The number of employees that were absent from 6 up to 12 days is =

Frequency\  for\  class\ [6\ -\ 9]+Frequency\  for\  class\ [9\ -\12]=14+6\\=20

Thus, there were 20 employees who were absent from 6 up to 12 days.

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3 years ago
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X=4
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