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3 years ago

Is -4 a solution of the equation 16\C =4

1 answer:

4 0

No it isn't.

16/C=4
Multiply c on both sides
16=4c
Divide 4 on both sides
Final Answer: 4=c

And so -4 is not the solution of this equation.

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Find the value.plzzz I will mark as the brillianest plzzzzzzzzzzzzzzzzzzzz

Aleks [24]

Answer:

n= 75

y= 75

z= 50

p= 105

other n across from p= 105

Step-by-step explanation:

n and y are the same since the triangle is isoseles.

p is supplemetary to n

z and 50 are opposites in a quadrilateral

7 0

3 years ago

Simplify the expression

KonstantinChe [14]

Answer:

9/4

Step-by-step explanation:

5×|-2-7(3)|-2×17

5×|-2-21|-34

5×|-23|-34

5×23-34

115-34=81

22+sq rt(7×28) 28=4×7 sq rt= 2×2×7×7

22+2×7=22+14=36

81÷9/36÷9=9/4

7 0

3 years ago

Read 2 more answers

Of the computer games Lynne owns, 5-12 are sport games and 3-12 are educational. What fraction of the games are either sport gam

Serhud [2]

Of 5 out of 12 (5/12) are sports games and 3 out of 12 (3/12) are educational, then you would add these together because you need a total for both because it would include one or the other, so both.

5/12 + 3/12= 8/12 or 2/3 are one or the other.

8 0

4 years ago

Read 2 more answers

Which is the measure of line segment AB? A)10 feet B)15 feet C)20 feet D)100 feet

zavuch27 [327]

Find the last angle:
180-(30+90)
180-(120)
60

Evaluate using sine rule:
$\frac{c}{sinC}$ = $\frac{b}{sinB}$

c= $\frac{bsinC}{sinB}$

= $\frac{10sin90°}{sin30°}$

=20

The length of line segment AB is 20 feet (answer choice C)

5 0

3 years ago

Read 2 more answers

Divide 12x 4 y 4 by 3x 2 y. A. 4x 6y 5 B. 4x 2y 3 C. 9x 6 D. 9x 2y 3

andrew-mc [135]

Answer:

$\frac{12x^4y^4}{3x^2y}=4x^2y^3$

Step-by-step explanation:

Consider an element $a\neq 0$

We know that $\frac{a^m}{a^n}=a^{m-n}$

Here, m and n are exponents and a is a base. Exponent refers to the no. of times a term is multiplied by itself. Another word for exponents is powers.

Other Properties of exponents:

$a^m\times a^n=a^{m+n}\\a^0=1\\\left ( a^m \right )^n=a^{mn}$