the flagpole cast an 8-foot Shadow as shown in the table the same time the oak tree cast a 12-foot Shadow how tall

1.How much taller Porter is than Henry, given that Porter is n inches tall and Henry is m inches tall. 2.How many times as tall

EleoNora [17]

Answer:

Porter is $n-m$ inches taller than Henry.

Porter is $\frac{n}{m}$ times taller than henry.

Step-by-step explanation:

The difference in height can be found using subtraction.

Since Porter is taller than Henry, we'll subtract away Henry's height from Porter's height. This will leave us with only the difference between the heights.

n = Porter's height

m = Henry's height

Difference in height is thus:

$n-m$

Answer: Porter is $n-m$ inches taller than Henry.

To find out how many times taller Porter is than Henry, we can use division.

An example: if Porter was 200cm, and Henry was 100cm, Porter is obviously 2 times as tall.

If we divide Porter's height by Henry's height...

$\frac{200}{100}=2$

..we'll get 2. This is because Henry's height "fits in twice" in Porter's height. 100 fits twice in 200.

Using our values, n and m, we'll divide n by m.

$\frac{n}{m}$

Answer: Porter is $\frac{n}{m}$ times taller than henry.

3 0

4 years ago

Six times a number is less than 60

lys-0071 [83]

Six times nine equals 54 so there is your answer

7 0

3 years ago

Is the data set “the number of leaves on a branch” quantitative or qualitative? If it is quantitative, is it discrete or continu

bazaltina [42]

It is quantitive and from that, I'm pretty sure it's discreet, sorry if the second part isn't very helpful.

5 0

3 years ago

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Fernando has two equally-sized containers of clay which he is using to build a pyramid-like structure. The finished structure wi

evablogger [386]

Answer:

Fernando does not have enough clay to finish the structure since, the expressions for the volume left are not the same.

Step-by-step explanation:

Let w be the length of the longest slab. Since each slab is 2 inches less than the one beneath it, we have the width of the other 3 slabs as w - 2, w - 2 - 2 = w - 4 and w - 4 - 2 = w - 6 respectively.

Since the base of each slab is a square and has thickness 2 inches, the volume of each slab from largest to smallest is thus 2w², 2(w - 2)², 2(w - 4)² and 2(w - 6)² respectively.

We have that we have half of the container of clay left after forming the first two slabs(which are the bottom-most slabs). Let V be the volume of each clay container. Since we have half left, that is V/2, we have used 2V - V/2 = 3V/2 to make the two bottom-most slabs.

So, 3V/2 = 2w² + 2(w - 2)²

= 2w² + 2(w² - 4w + 4)

= 2w² + 2w² - 8w + 8

= 4w² - 8w + 8

= 4(w² - 2w + 2) (1)

Also we want to know if V/2 is equal to the volume of the two top-most slabs.

So, V/2 = 2(w - 4)² + 2(w - 6)²

= 2(w² - 8w + 16) + 2(w² - 12w + 36)

= 2w² - 16w + 32 + 2w² - 24w + 72

= 4w² - 40w + 104

= 4(w² - 10w + 26)

From (1) V/2 = 4(w² - 2w + 2)/3 ≠ 4(w² - 10w + 26)

<u>Since the expressions for the remaining volume are not the same, Fernando does not have enough clay to finish the structure.</u>

4 0

3 years ago

HELP PLEASE YOU'LL GET 25 POINTS

ollegr [7]

Answer:

50

Step-by-step explanation:

Im pretty sure

5 0

3 years ago

Read 2 more answers