To solve this, we are going to use the formula for the area of the sector of a circle:
where
is the area of the circular sector.
is the radius of the circle.
is the central angle in radians.
We know form our problem that that the measure of the central angle is 1 radian, so
. We can also infer from the picture that the radius of the circle is 3in, so
. Lets replace those values in our formula to find
:
We can conclude that the area of the circular sector in the picture is
4.5 square inches.
To prove that the arc length is indeed 3 inches, we are going to use the formula:
where
is the arc length.
us the radius of the circle.
is the central angle.
We know from our problem that
, and
, so lets replace those values in our formula:
We can conclude that the length of the arc is indeed
3 inches.
Answer:
30°
Step-by-step explanation:
TW UV
If an ARC subtends an angle in the circle (on the opposite side of the circumference), the measure of that angle will be HALF of the Arc. In other words, the Arc's measure will be DOUBLE of that angle.
The measure of the angle would be SAME if the angle subtended in the center of the circle, thought.
Now, looking at the image, we can see that:
Arc TW subtends Angle V and Angle U
*on the opposite side of the circumference*
So,
Angle V (measure given to be 30) is HALF of Arc TW, so
Arc TW = 2 * 30 = 60
So, Angle U is half of Arc TW
60/2 = 30
Hence,
<u>∠U = 30°</u>
Answer:
x = 11.31
y = 13.86
z = 19.60
Step-by-step explanation:
8/x = x/16
x^2 = 128
x = 11.31
x^2 + 8^2 = y^2
128 + 64 = y^2 = 192
y = 13.86
x^2 + 16^2 = z^2
128 + 256 = z^2
z^2 = 384
z = 19.60
To figure this you would subtract, I believe.
So let’s try it...
300-3= 297
And that would make 300 297 much greater than 3.
Have a nice night and happy learning!
~Brooke❤️
Answer:
x = 1± 3i
Step-by-step explanation:
x^2-2x+10=0
We can complete the square to solve by subtracting 10 from each side
x^2-2x+10-10=-10
x^2 -2x = -10
We need to add (2/2) ^2 to each side or 1
x^2 -2x+1 = -10 +1
x^2 -2x+1 = -9
The left side factors into (x- (2/2) ) ^2
(x-1) ^2 = -9
Take the square root of each side
sqrt((x-1) ^2 =± sqrt(-9)
x-1 = ±sqrt(-1) sqrt(3)
Remember the sqrt(-1) = i
x-1 = ± 3i
Add 1 to each side
x-1+1 = 1± 3i
x = 1± 3i