SUMMER SCHOOL PLZ HELP

Mathematics

1 answer:

LuckyWell [14K]3 years ago

8 0

Question 1:
The labeled points are points from the drawing are:
A,B,C,D,E

Question 2:
The intersection of the two lines is a point since the necessary condition for the two lines to intersect is that they should be on the same plane, hence they form a point.
Thus the correct answer is: True

Question 3:
The name for a given line is given from the end points that forms the line. Hence given that the two points forming the line is B and P, the correct answer is option C]

Question 4:
There are 5 letters and you use 2 to name the line, so the number of choices will be given by:
5C2=5!/(2!(5-2)!)
=(5×4×3×2×1)/(2×1×3×2×1)
=10

Question 5:
Collinear points are three or more points which lie on the same single straight line. In our case the points are:
T,X,V

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Assume that adults have IQ scores that are normally distributed with a mean of mu equals 105 and a standard deviation sigma equa

Sindrei [870]

Answer:

0.7698

Step-by-step explanation:

If you call your random variable $X$ , then what you are looking for is

$P(87 \leq X \leq 123)$

because you want the probability of $X$ being <em>between 87 and 123.</em>

We need a table with of the normal distribution. But we can only find the table with $\mu = 0$ and $\sigma = 1$ . Because of that, first we need to <em>normalize </em>our random variable:

$Z = \frac{X - \mu}{\sigma} = \frac{X - 105}{15}$

(you can always normalize your variable following the same formula!)

now we can do something similar to our limits, to get a better expression:

$\frac{87 - 105}{15} = \frac{-18}{15} = -1.2$

$\frac{123 - 105}{15} = \frac{18}{15} = 1.2$

And we transform our problem to a simpler one:

$P(87 \leq X \leq 123) = P(-1.2 \leq Z \leq 1.2) = P(Z \leq 1.2) - P(Z \leq -1.2)$

(see Figure 1)

From our table we can see that $P(Z \leq 1.2) = 0.8849$ (this is represented in figure 2).

Remember that the whole area below the curve is exactly 1. So we can conclude that $P(Z \geq 1.2) = 0.1151$ (because 0.8849 + 0.1151 = 1). We also know the normal distribution is symmetric, then