Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
Answer:
25.6-14.07= 11.53
Step-by-step explanation:
Answer: 315 miles
Step-by-step explanation:
let onward speed = x mph, then distance = 7x
return speed = (x+18) mph, (same) distance = 5(x+18)
equating the two,
7x = 5(x+18)
2x = 90 ==> x = 45 mph
so distance = 7*45 = 315 miles
12/15 = x/100
Multiply 12 x 100 to get 1,200/15 is 80.
Because 25 x 4 = 100, you divide 80 by 4.
Your answer is 20.
The answer is D.191
4(2(25)-2)-1
4(50-2)-1
4(48)-1
192-1
191
